Question

The SI units for acceleration are km/h

Answer 1

7. The rate at which the velocity of an object changes is the object's rate of acceleration.

8. Each second its speed increases by  8 m/s.

9. The distance the airplane travels each second is 8 m than the distance it traveled during the previous second

10. The ride's rate of acceleration during the  4 seconds is $10 m/s^2$

Explanation:

7)

The acceleration of an object is defined as the rate of change in velocity of the object. Mathematically:

$a=\frac{v-u}{t}$

where

u is the initial velocity of the object

v is the final velocity

t is the time taken for the object's velocity to change from u to v

Acceleration is measured in meters per second squared ($m/s^2$), and it basically gives a measure of how fast the velocity of an object changes.

Since velocity is a vector quantity, acceleration is a vector quantity as well: this means that an object is accelerated not only when its speed changes, but also when the direction of its velocity changes (for example, in a circular motion).

8)

The velocity of an object moving at constant acceleration is given by

$v=u+at$

where

u is the initial velocity

v is the velocity at time t

a is the acceleration

We can rewrite it as

$v-u=at$

where $(v-u)$ represents the change in velocity.

For the plane in this problem, its acceleration is

$a=8 m/s^2$

So, the change in velocity in a time of $t=1 s$ is

$(v-u) = at=(8)(1)=8 m/s$

9)

The distance covered by an object moving at constant acceleration in a time $t$ is

$s=ut+\frac{1}{2}at^2$

where u is the velocity at the beginning of the time t considered, a is the acceleration, s is the distance covered.

So, the distance covered in a certain second $t_1 = 1 s$ is

$s_1 = u t_1 + \frac{1}{2}at_1^2 = 1u+\frac{1}{2}(8)(1)^2 = u+4$

After that second, the new velocity is

$u'=u+at_1 = u+(8)(1) = u+8$

The distance travelled in the next second is

$s_2 = u' t_2 + \frac{1}{2}at^2 = (u+8)(1) + \frac{1}{2}(8)(1)^2=u+8+4=u+12$

So, the difference in the distance travelled in the next second and in the previous second is

$s_2-s_1 = (u+12)-(u+4)=8 m$

10)

The acceleration of the ride is given by

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time interval

Here we have

u = 0 m/s

v = 40 m/s

t = 4 s

Substituting,

$a=\frac{40-0}{4}=10 m/s^2$

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly