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3 years ago

A frog jumps for 4.0 seconds at a maximum horizontal distance of 0.8m. what is its velocity along the road?

Physics

1 answer:

Lerok [7]3 years ago

3 0

Answer:

The frog's horizontal velocity is 0.2 m/s.

Explanation:

To solve this problem, we must first remember what velocity is and how we solve for it. Velocity can be solved for using the formula x/t, where x represents horizontal distance and t represents time (in seconds), that it takes to travel this distance. If we plug in the given numbers for these variables and solve, we get the following:

v = x/t

v = 0.8m/4s

v = 0.2 m/s

Therefore, the correct answer is 0.2 m/s. We can verify that these units are correct because the formula calls for distance divided by time, so meters per second is a sensible answer.

Hope this helps!

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The sun’s absolute magnitude is described as _______ in comparison to other stars.

cupoosta [38]

very small

Being close to the earth can be milseading. I think that if the sun were at the same distance as anohter star, it might be hard to see because it is small, relatiavely speaking

3 0

3 years ago

Read 2 more answers

Please show all the steps and work. The answer is -3.9 m/s2

konstantin123 [22]

Given that,

Initial velocity of the airplane = 66 m/s

Distance = 560 m

Final velocity of the airplane = 0 (stops)

To find,

Acceleration of the airplane.

Solution,

Let us consider that a is the acceleration of the airplane. We can find it using third equation of motion as follows :

$v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{0^2-66^2}{2(560)}\\\\a=-3.9\ m/s^2$

Therefore, the acceleration of the airplane is $-3.9\ m/s^2$

8 0

3 years ago

A passenger on an interplanetary express bus traveling at = 0.95 takes a 9.0-minute catnap, according to her watch.How long does

Nimfa-mama [501]

Answer:

28.82 minutes

Explanation:

This problem is an example of time dilatation by acceleration. The formula is:

$\Delta t=\gamma \Delta t_0=\frac{\Delta t_0}{\sqrt{1-\frac{v^2}{c^2} }}$

$\Delta t$ is the time measured by the observer on a fixed position (in this case in the fixed planet), $\Delta t_0$ is the time measured by the person moving away from the fixed observer (the one on an interplanetary express bus), $c$ is the speed of light and $v$ the velocity of the observer that is moving away (the velocity of the ship).

$\Delta t_0=9 min=540s\\\Delta t=\frac{540}{\sqrt{1-\frac{(0.95c)^2}{c^2}}}=\frac{540}{\sqrt{1-\frac{0.95^2c^2}{c^2}}}=\frac{540}{\sqrt{1-0.95^2}}\\\Delta t=\frac{540}{\sqrt{1-0.9025}}=\frac{540}{\sqrt{0.0975}}=\frac{540}{0.3122}=1729.38s\\\Delta t=28.82minutes$

6 0

4 years ago

Which statement correctly describes the amount of force applied by the wall as the student conditions to apply a 250-newton forc

Tatiana [17]

B) The wall pulls with a force of 250 N against the force

Explanation:

We can answer this question by using Newton's third law of motion, which states that:

<em>"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"</em>

In this situation, the student is applying a force of 250 N on the wall. We can identify this force as the action. Therefore, this means (according to Newton's third law) that the wall will also apply a force (the reaction) of equal magnitude (so, 250 N), in the opposite direction to the original force.

Therefore, the correct statement is

B) The wall pulls with a force of 250 N against the force

Learn more about Newton's third law:

brainly.com/question/11411375

#LearnwithBrainly

8 0

3 years ago

_____________________ are structures in cardiac muscle tissue that allow impulses to spread across the heart more rapidly.

Darya [45]

Gap junctions in the intercalated discs allow impulses to be spread across the heart more quickly. This is because gap junctions allow particles/signals to pass through, thus making cells with gap junctions more able to interact.

One more thing—you posted this in the physics section rather than biology.

8 0

4 years ago