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Kryger [21]
2 years ago
7

What direction does tangential velocity point?

Physics
1 answer:
dmitriy555 [2]2 years ago
3 0

Answer:b.outward in a straight line tangent to the circle!

Explanation:at any given point on the circle is always along the tangent line.

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A dog walking to the right with a speed of 1.5 m/s sees a cat and speeds up with a constant rightward acceleration of magnitude
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Answer: 8.62

Explanation: It’s correct answer:)

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100 J of work in 10 seconds
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The average power is 10 watts. What's the question ?
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A spherical balloon has a radius of 7.40 m and is filled with helium. Part A How large a cargo can it lift, assuming that the sk
malfutka [58]

Answer:

The mass of the cargo is M  =  188.43 \ kg

Explanation:

From the question we are told that

    The radius of the spherical balloon is  r =  7.40 \ m

     The mass of the balloon is  m = 990\ kg  

The volume of the spherical balloon is mathematically represented as

     V  =  \frac{4}{3} * \pi r^3

substituting values

      V  =  \frac{4}{3} * 3.142 *(7.40)^3

      V  =  1697.6 \ m^3

The total mass  the balloon can lift is mathematically represented as

     m =  V (\rho_h - \rho_a)

where \rho_h is the density of helium with a  value of

       \rho_h  =  0.179 \ kg /m^3

and  \rho_a is the density of air with a value of

        \rho_ a  = 1.29 \ kg / m^3

substituting values

          m =  1697.6 ( 1.29  - 0.179)

         m =  1886.0  \ kg

Now the mass of the cargo is mathematically evaluated as

        M  =  1886.0 - 1697.6

        M  =  188.43 \ kg

       

5 0
3 years ago
A 320 g air track cart traveling at 1.25 m/s collides with a stationary 270 g cart. What is the speed of the 270 g cart after th
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Answer:

The speed of the 270g cart after the collision is 0.68m/s

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Mass of air track cart (m1) = 320g

Initial velocity (u1) = 1.25m/s

Mass of stationary cart (m2) = 270g

Velocity after collision (V) = m1u1/(m1+m2) = 320×1.25/(320+270) = 400/590 = 0.68m/s

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How does an atom of bromine-79 become a bromide ion with a -1 charge?
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a the atom loses 1 proton to have a total of 34

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