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Liula [17]
3 years ago
10

A heat engine with a thermal efficiency of 45 percent rejects 500 kj/kg of heat. how much heat does it receive

Physics
1 answer:
adell [148]3 years ago
8 0
Alot as far as i know unless you need it in formal terms.
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Porque alguno satélites de telecomunicaciones puede permanecer en una orbita geoestacionaria
agasfer [191]
<span>Es para la comodidad del cliente. <span>Si el satélite no estaba parado
en el cielo, entonces el cliente tendría que seguir moviendo su plato
para seguir el satélite.</span></span>
4 0
3 years ago
A boy starts from point A and walks 3 meters toward the south, then turns around and walks 7 meters toward the north. What is th
jolli1 [7]

Answer:

-3m+7m =  4m

Explanation:

As he walks south, he is going down 3m (-3m). Then he walks up 7m (+7m).

You subtract the final position from the initial position to get displacement.

7m - 3m = 4m

7 0
3 years ago
Find the power load P in kilowatts of an electrical circuit that takes a current I of 17 amperes at a voltage V of 320 volts if
MA_775_DIABLO [31]

Answer: P = 5.44 KW

Explanation:

The formula for calculating power is expressed as

P = VI

where

v is the voltage

I is the current

From the information given,

v = 320

I = 17

Thus,

P = 320 x 17 = 5440 W

We would convert it to KW by dividing by 1000. It becomes

P = 5440/1000

P = 5.44 KW

6 0
1 year ago
Plz help it’s passed due!
pickupchik [31]
It is b 9.1 :) have a nice day
5 0
3 years ago
A wire 40cm long and of diameter 0.60mm has a resistance of 1.5 ohm what is the resistivity of the material of which it is made
zavuch27 [327]

Answer:

The resistivity of the wire is 1.05\times 10^{-6}\ \Omega-m

Explanation:

We have,

Length of a wire is 40 cm or 0.4 m

Diameter of a wire is 0.60 mm

Radius is 0.3 mm or 0.0003 m

Resistance of a wire is 1.5 ohm

Now we need to find the resistivity of the material of which it is made. The resistance of a wire in terms of its resistance, length and area is given by :

R=\rho \dfrac{l}{A}

\rho = resistivity

\rho=R \dfrac{\pi r^2}{l}\\\\\rho=1.5\times  \dfrac{3.14\times (0.0003 )^2}{0.4}\\\\\rho=1.05\times 10^{-6}\ \Omega-m

So, the resistivity of the wire is 1.05\times 10^{-6}\ \Omega-m.

3 0
3 years ago
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