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jekas [21]
3 years ago
6

Why are logarithmic scales useful in earth science?

Physics
1 answer:
Yuri [45]3 years ago
4 0
The differences in energy released by earthquakes are too large to express with linear scales.
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A bullet of mass 20g is a fired with a velocity of 50mls from a gun of mass 2.5kg. Calculate the recoil velocity of the gun.​
jok3333 [9.3K]

Answer:

v = - 0.4 m/s

Explanation:

Initial momentum is zero as neither gun nor bullet have velocity

Conservation of momentum

0 = 0.020(50) + 2.5v

v = - 0.4 m/s

3 0
3 years ago
Static electric fields are caused by charged particles. What characterizes a positively charged particle?
sergeinik [125]

Static electric fields are caused by charged particles when the atoms which compose the particle will have the same number of electrons as protons.

Each point in space has an electric field associated with it when the charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.

Both the electromagnetic wave produced by a radio broadcast monopole antenna and the field created in the dielectric of a parallel-plate capacitor are examples of electric fields (which create a time-varying field). Every place in space where a charge, regardless of its shape, is present is said to have an electric field, which is an electric attribute. The electric field's equation is given as E = F / Q.

To learn more about electric field please visit -
brainly.com/question/15800304
#SPJ1

8 0
2 years ago
A woman pulls on a 6.00-kg crate, which in turn is connected to a 4.00-kg
djverab [1.8K]

Answer:

B. is subject to a smaller net force but same acceleration.

Explanation:

F = m*a

So because our force applied is constant from the women pulling on the rope which means the acceleration is the same on both the 4kg create and the 6kg create. The only thing that changes here is the mass of the creates, so there is more tension force between the women and the 6kg create then there is between the 4kg create and the 6kg. It takes less force to move the 4kg create therefore the tension force is less between the two creates.

7 0
3 years ago
Read 2 more answers
The harmonic law would suggest that Neptune will take _____ to orbit the Sun than Mercury.
ivolga24 [154]

The correct answer is The harmonic law would suggest that Neptune will take a longer amount of time to orbit the sun then Mercury!

You Can find this out from Planetary Motion!:)

6 0
3 years ago
Read 2 more answers
A block weighing 400 kg rests on a horizontal surface and supports on top of it ,another block of weight 100 kg which is attache
Paladinen [302]

Answer:

F_a=1470\ N

Explanation:

<u>Friction Force</u>

When objects are in contact with other objects or rough surfaces, the friction forces appear when we try to move them with respect to each other. The friction forces always have a direction opposite to the intended motion, i.e. if the object is pushed to the right, the friction force is exerted to the left.

There are two blocks, one of 400 kg on a horizontal surface and other of 100 kg on top of it tied to a vertical wall by a string. If we try to push the first block, it will not move freely, because two friction forces appear: one exerted by the surface and the other exerted by the contact between both blocks. Let's call them Fr1 and Fr2 respectively. The block 2 is attached to the wall by a string, so it won't simply move with the block 1.  

Please find the free body diagrams in the figure provided below.

The equilibrium condition for the mass 1 is

\displaystyle F_a-F_{r1}-F_{r2}=m.a=0

The mass m1 is being pushed by the force Fa so that slipping with the mass m2 barely occurs, thus the system is not moving, and a=0. Solving for Fa

\displaystyle F_a=F_{r1}+F_{r2}.....[1]

The mass 2 is tried to be pushed to the right by the friction force Fr2 between them, but the string keeps it fixed in position with the tension T. The equation in the horizontal axis is

\displaystyle F_{r2}-T=0

The friction forces are computed by

\displaystyle F_{r2}=\mu \ N_2=\mu\ m_2\ g

\displaystyle F_{r1}=\mu \ N_1=\mu(m_1+m_2)g

Recall N1 is the reaction of the surface on mass m1 which holds a total mass of m1+m2.

Replacing in [1]

\displaystyle F_{a}=\mu \ m_2\ g\ +\mu(m_1+m_2)g

Simplifying

\displaystyle F_{a}=\mu \ g(m_1+2\ m_2)

Plugging in the values

\displaystyle F_{a}=0.25(9.8)[400+2(100)]

\boxed{F_a=1470\ N}

8 0
3 years ago
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