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DENIUS [597]
2 years ago
8

What does energy and Newton's Laws (all three) have to do with roller coasters?

Physics
2 answers:
Kipish [7]2 years ago
7 0

Answer:

Potential Energy is the energy that is waiting to be released like at the top of the roller coaster, Kinetic energy is the energy that is moving the rollercoaster downhill fast.

Three Laws:

The rollercoaster will rest at the top, and then the gears will make it move downhill, and make it stop.

The gears make the rollercoaster move, and in reaction, it pushes back on the gears.

Tems11 [23]2 years ago
6 0

Answer:

Newton's law has every thing to do with roller coasters.

in the case that you have given, the first law states that any object when given an force will keep moving until there is no opposing force acting upon the moving object. when the roller coaster is moving the opposing force here can be the frictional force that is acting upon the coaster that is the breaking system as the train comes to the station to stop a the end.

to summarize

Newton's first law: any object will keep moving until there is an opposing force acting upon it

the opposing force in the coaster is the breaking system..

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When calculating the net electrostatic force, a negative value indicates that the two charged objects involved __________.
DiKsa [7]

Answer:

B

Explanation:

The correct answer is B) have unlike charges. Since they are attracted to each other they have to be unlike

5 0
3 years ago
A 1500 kg elevator, suspended by a single cable with tension 16.0 kN, is measured to be moving upward at 1.2 m/s. Air resistance
kirill115 [55]

Tension in the Cable is 0.87 m/s6^2, Elevator's speed after it has moved 10m is 1.6*10^5 N, Work done by gravity is  1.47 * 10^3 N, Elevator Kinetic Energy is 13897.5J and Elevator Speed after rising to 10m is 4.312 m/s.

Tension is a pulling force that operates in one dimension along the cables' axes in the opposite direction from the direction of the applied force. The combined weight of the elevator box and the passenger riding inside it, in the case of an elevator, provides the pulling force in the cables is called Tension.

A moving object or particle's kinetic energy, which depends on both mass and speed, is one of its characteristics. The type of motion can be vibration, translation, rotation around an axis, or any combination of these. Kinetic energy is a type of energy that an item or particle possesses as a result of motion.

We know that,

Tension in the Cable

T = m(g+a)  = g+a = T/m = 16 * 103 / 1500 = 10.67 m/s2

a = 10.67 - 9.8 = 0.87 m/s6^2

Elevator's speed after it has moved 10m.

U^2 = u^2 +2as

= 1.22 +2*0.87*10

=1.6*10^5 N

Work done by gravity  = mg * 10 = 14700 * 10 = 1.47 * 10^3 N

Elevator Kinetic Energy = 1/2 mv^2 = 1/2*1500*18.53 = 13897.5J

Elevator Speed after rising to 10m ,

U^2 = u^2 +2as =  1.2 +2*0.87*10 = 18.6

U =(18.6)^1/2=4.312 m/s

Learn more about Kinetic Energy here

brainly.com/question/26472013

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6 0
1 year ago
How are electric and magnetic forces the same? How are they different?
qaws [65]
They both have a certain force. They are different because that force is different
3 0
2 years ago
Which discovery did Galileo make to support the theory that the planets, including Earth, orbit the Sun?
const2013 [10]

The answer to your quesiton is,

A) Venus has phases.

-Mabel <3

7 0
3 years ago
Read 2 more answers
For a damped simple harmonic oscillator, the block has a mass of 1.2 kg and the spring constant is 9.8 N/m. The damping force is
ArbitrLikvidat [17]

Answer:

a) t=24s

b) number of oscillations= 11

Explanation:

In case of a damped simple harmonic oscillator the equation of motion is

m(d²x/dt²)+b(dx/dt)+kx=0

Therefore on solving the above differential equation we get,

x(t)=A₀e^{\frac{-bt}{2m}}cos(w't+\phi)=A(t)cos(w't+\phi)

where A(t)=A₀e^{\frac{-bt}{2m}}

 A₀ is the amplitude at t=0 and

w' is the angular frequency of damped SHM, which is given by,

w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

Now coming to the problem,

Given: m=1.2 kg

           k=9.8 N/m

           b=210 g/s= 0.21 kg/s

           A₀=13 cm

a) A(t)=A₀/8

⇒A₀e^{\frac{-bt}{2m}} =A₀/8

⇒e^{\frac{bt}{2m}}=8

applying logarithm on both sides

⇒\frac{bt}{2m}=ln(8)

⇒t=\frac{2m*ln(8)}{b}

substituting the values

t=\frac{2*1.2*ln(8)}{0.21}=24s(approx)

b) w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

w'=\sqrt{\frac{9.8}{1.2}-\frac{0.21^{2}}{4*1.2^{2}}}=2.86s^{-1}

T'=\frac{2\pi}{w'}, where T' is time period of damped SHM

⇒T'=\frac{2\pi}{2.86}=2.2s

let n be number of oscillations made

then, nT'=t

⇒n=\frac{24}{2.2}=11(approx)

8 0
3 years ago
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