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enyata [817]
3 years ago
8

A rock falls from rest off a high cliff. How much time does it take for the rock to reach a speed of 40 m/s? [ignore air resista

nce.]
Physics
1 answer:
grigory [225]3 years ago
3 0

Answer:THERE

Explanation:

10,M/S.

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Three carts of masses 4.0 kg, 10kg, and 3.0 kg move on a frictionless track with speeds of v1 = 5.0m/s, v2=3.0m/s, and v3=-3.6 m
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2.24 m/s is the calculated velocity.

Initial velocity (u) squared plus two times the acceleration (a) times the displacement equals final velocity (v) squared (s). Final velocity (v) is equal to the square root of initial velocity (u) squared plus two times the acceleration (a) times displacement when v is the variable being solved for (s).

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v1 = 5.00 m/s = 5.00 m/s, v2 = 3.00 m/s = 3.00 m/s, v3 = -4.00 m/s = 4.00 m/s, and m1v1+m2v2+m3v3 = (m1+m2+m3) v=d frac m 1v 1+m 2v 2+m 3v 3, where (m1+m2 + m3) is the product of (v1 v 1+m2v2+m3v3).

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the three carts' final velocities are calculated as follows: v=d frac

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2.24 m/s is the calculated final velocity.

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