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3 years ago

What are the magnitude and direction of electric field at the center of square?

Physics

1 answer:

Kobotan [32]3 years ago

6 0

Answer:

hello the diagram related to this question is missing attached below is the missing diagram

Answer :

The magnitude of the electric field = 4KQ / L^2

direction = 45° east to south

Explanation:

The magnitude of the electric field = 4KQ / L^2

direction = 45° east to south

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Choose the statement that is a misconception about a system in chemical equilibrium. (2 points) The rate of the forward reaction

almond37 [142]

Answer:

The correct answer is "The reactions stop once equilibrum is achieved"

Explanation:

A system is said to have attained equilibrium when the rate of forward reaction is the same/equal to the rate of backward reaction. The reaction below shows a chemical reaction that is at equilibrium

2N₂O₅ (aq) ⇄ 4NO₂ (aq) + O₂ (aq)

An equilibrium reaction is always a reversible reaction. <u>When the system is at equilibrium (when there is a balance), the concentration of the reactants and products do not change despite the fact that reaction does not stop</u>; what happens however is that the rate at which the reactant(s) are formed (backward reaction) will be equal to the rate at which the product(s) are formed (forward reaction).

From the explanation above, it can be deduced that "The reactions stop once equilibrum is achieved" is a misconception about a system in chemical equilibrium.

8 0

3 years ago

A hockey puck slides off the edge of a table with an initial velocity of 23.2 m/s and experiences no air resistance. The height

Dennis_Churaev [7]

Answer:

15.1°

Explanation:

The horizontal velocity of the hockey puck is constant during the motion, since there are no forces acting along this direction:

$v_x = 23.2 m/s$

Instead, the vertical velocity changes, due to the presence of the acceleration due to gravity:

$v_y(t)= v_{y0} -gt$ (1)

where

$v_{y0}=0$ is the initial vertical velocity

g = 9.8 m/s^2 is the gravitational acceleration

t is the time

Since the hockey puck falls from a height of h=2.00 m, the time it needs to reach the ground is given by

$h=\frac{1}{2}gt^2\\t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2.00 m)}{9.8 m/s^2}}=0.64 s$

Substituting t into (1) we find the final vertical velocity

$v_y = -(9.8 m/s^2)(0.64 s)=-6.3 m/s$

where the negative sign means that the velocity is downward.

Now that we have both components of the velocity, we can calculate the angle with respect to the horizontal:

$tan \theta = \frac{|v_y|}{v_x}=\frac{6.3 m/s}{23.2 m/s}=0.272\\\theta = tan^{-1} (0.272)=15.1^{\circ}$

6 0

3 years ago

An object has a mass of 15 kg and is accelerating to the right at 16.3 m/s2. The free-body diagram shows the horizontal forces a

marshall27 [118]

Refer to the free body diagram shown melow.

F = applied force
R = frictional force
m = 15 kg, the mass of the object

The acceleration (to the right) is 16.3 m/s², therefore
F - R = (15 kg)*(16.3 m/s²) = 244.5 N

The normal reaction is
N = mg = (15 kg)*(9.8 m/s²) = 147 N
The frictional force is
R = μN = 147μ N, where μ = coefficient of kinetic friction.

Let us check possible answers:
If R = 5.5 N, then μ = 5.5/147 = 0.0374 (very likely)
If R = 15 N, then μ = 15/147 = 0.102 (possible)
If R = 244.5 N, (Highly unlikely, exceed mg)
If R = 494.5 N, (highly unlikely, exceeds mg)

Answer:
The most reasonable answer is R = 5.5 N