All categories

4 years ago

Is most of the mass of an atom located in the nucleus or outside the nucleus how do you know?

1 answer:

7 0

Most of the mass is in the nucleus because the protons and neutrons are the heaviest particles, and electrons are nearly weightless.

You might be interested in

What is hydroelectric power ?<br><br> Answer quickly..!

GenaCL600 [577]

$\:$

<u>Hydroelectric power,</u> also called hydropower is the electricity produced from generators driven by turbines that convert the potential energy of falling or fast-flowing water into mechanical energy.

7 0

3 years ago

Read 2 more answers

Is the us warmer than antarctica?

Likurg_2 [28]

Answer:

Yes

Explanation:

Antarctica is usually always cold.

7 0

3 years ago

A 4300-N force from a car's engines produces an acceleration of 3.3 m/s2. What is the mass of the car?

sertanlavr [38]

Answer:The net force acting on the car is 3×103 Newtons

Explanation:

5 0

3 years ago

An Olympic diver springs off of a high dive that is 3 m above the surface of the water. When she lands in the water she is trave

klemol [59]

Answer: $u=4.51 m/s\ at\ angle\ of\ \theta =59.34^{\circ}$

Explanation:

Given

height of building h=3 m

Landing velocity of diver $v=8.90 m/s$ at an angle of $75^{\circ}$

Let u be the initial velocity of diver at an angle of \theta with horizontal

Since there is no acceleration in horizontal direction therefore horizontal component of velocity will remain same

$u\cos \theta =8.9\cos (75)$ ---- -----1

Considering Vertical motion

$v^2-u^2=2as$

here $v=8.9\sin (75)$

$u=u\sin \theta$

$s=3 m$

$a=9.8 m/s^2$

$(8.9\sin (75))^2-(u\sin \theta )^2=2\times 9.8\times 3$

$u\sin \theta =\sqrt{(8.9\sin 75)^2-(2\cdot 9.8\cdot 3)}$

$u\sin \theta =3.886$ ----------------2

Divide 2 and 1 we get

$\tan \theta =\frac{3.886}{8.9\cos (75)}$

$\tan \theta =1.687$

$\theta =59.34^{\circ}$

Thus $u\cos (59.34)=8.9\cos (75)$

$u=4.51 m/s$

7 0

3 years ago

The tires of a car make 77 revolutions as the car reduces its speed uniformly from 95.0 km/h to 65.0 km/h. The tires have a diam

nika2105 [10]

Answer:

Explanation:

95.0 km/hr = 26.39 m/s

65 km/hr = 18.06 m/s

Circumference of a tire is 0.9π m

77 revolutions is a distance of

77(0.9π) = 69.3π m

v² = u² + 2as

a = (v² - u²) / 2s

a = (18.06² - 26.39²) / (2(69.3π))

a = -0.85 m/s²

s = (v² - u²) / 2a

s = (0² - 26.39²) / 2(-0.85)

s = 409 m

5 0

3 years ago