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3 years ago

A 4300-N force from a car's engines produces an acceleration of 3.3 m/s2. What is the mass of the car?

Physics

1 answer:

sertanlavr [38]3 years ago

5 0

Answer:The net force acting on the car is 3×103 Newtons

Explanation:

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Please help me, I will give BRAINLIEST to the best answer

sdas [7]

Explanation:

a. A grocery bag as you lift it up

b. A crane moving dirt......

d. A crate as you push it along the floor

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3 years ago

Read 2 more answers

At launch a rocket ship weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 s to reach 161 km/h; at the end

SpyIntel [72]

Answer:

$5.590278\ m/s^2$

$7.74038461538\ m/s^2$

178.888896 m

12790.56 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{161}{3.6}-0}{8}\\\Rightarrow a=5.590278\ m/s^2$

The acceleration is $5.590278\ m/s^2$

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{1610}{3.6}-\dfrac{161}{3.6}}{60-8}\\\Rightarrow a=7.74038461538\ m/s^2$

The acceleration is $7.74038461538\ m/s^2$

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 5.590278\times 8^2\\\Rightarrow s=178.888896\ m$

Distance traveled in the first 8 seconds is 178.888896 m

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=\dfrac{161}{3.6}\times 52+\dfrac{1}{2}\times 7.74038461538\times 52^2\\\Rightarrow s=12790.56\ m$

Distance traveled during 8-60 second interval is 12790.56 m

6 0

3 years ago

Your dog (who weighs 20kg) has just fallen off a cliff! Oh no!! Luckily they were on a leash, and you (who weighs 70kg) was fort

Maksim231197 [3]

Answer:

yes

Explanation:

becasue 70 divided by 0.3 = >20

Hope I helped:)

3 0

2 years ago

An object that is accelerating may be

Elenna [48]

It must be either speeding up, or slowing down, or turning. There are no other possibilities.

6 0

2 years ago

A 55.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300. What h

MariettaO [177]

Answer:

161.86 N

Explanation:

mass of box m= 55.0 kg

weight of the box, mg= 55×9.81

g here is acceleration due to gravity =9.81 m/sec^2

coefficient of friction between the box and the surface μ= 0.3

the friction force F_s= μmg= 0.3×55×9.81

=161.86 N

to move the ball horizontal force required is 161.86 N

8 0

3 years ago