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goldenfox [79]
3 years ago
10

A carboxyl group is made up of ____. a. one nitrogen atom and two hydrogen atoms b. one hydrogen atom, two oxygen atoms, and one

carbon atom c. one hydrogen atom and two carbon atoms d. one carbon atom, one oxygen atom, and one hydrogen atom
Chemistry
1 answer:
erik [133]3 years ago
4 0
B. One hydrogen atom , two oxygen atoms and one carbon atom -COOH. This is carboxylate group!
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The results of a classroom group activity performed to test the acidic or basic nature of two substances are shown in the table.
Yuliya22 [10]

Answer:

I need the table to do the question

Explanation:

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The metric system of units is known as the
sweet-ann [11.9K]

Answer:

Centimeters

Explanation:

Lenght cm

4 0
3 years ago
The process n01 → p11 + β−10 n 0 1 → p 1 1 + β - 1 0 represents a(n) _____.
polet [3.4K]

Answer:

  • <u><em>beta decay</em></u>

Explanation:

The <em>process</em> is represented by the nuclear equation:

  • ^1_0n → ^1_1p+^0_{-1}\beta

Where:

  • n represents a neutron,
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The superscripts to the leff of each symbol is the mass number (number of protons and neutrons), and the subscript to the left means the atomic number (number of protons).

Then, in this process a neutron is being transformed into a proton by the emssion of an electron (from inside the nucleus of the atom).

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5 0
4 years ago
You have 4.5 x 10^24 particles of C3H8. How many grams are present?
Citrus2011 [14]

Answer:

33 g.

Explanation:

Hello there!

In this case, for these particle-mole-mass relationships problems, it is necessary for us to recall the following equivalence statement, based off the molar mass of the involved compound, C3H8, one mole of particles and the Avogadro's number:

1mol=44.11g=6.022x10^{23}molecules

In such a way, we can set up the following expression for the calculation of the mass in the given particles of propane:

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Best regards!

3 0
3 years ago
A 2.5 mol sample of phosphorus pentachloride, PCl5 dissociates at 160C and 1.00atm to give 0.338 mol of phosphorus trichloride a
Readme [11.4K]

Explanation:

Moles of phosphorus pentachloride present initially = 2.5 mol

Moles of phosphorus trichloride at equilibrium = 0.338 mol

PCl_5\rightleftharpoons PCl_3+Cl_2

Initially

2.5 mol      0    0

At equilibrium:

(2.5 - x) mol      x     x

So, from above, the moles of phosphorus trichloride at equilibrium , x= 0.338 mol

Mass of 0.338 moles of  phosphorus trichloride at equilibrium:

= 0.338 mol × 137.5 g/mol = 46.475 g

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= (2.5 - 0.338) mol = 2.162 mol

Mass of 2.162 moles of  phosphorus pentachloride at equilibrium:

= 2.162 mol × 208.5 g/mol = 450.777 g

Moles of chloride gas present at equilibrium : 0.338 mol

Mass of 0.338 moles of chloride gas at equilibrium:

= 0.338 mol × 71 g/mol = 23.998 g

3 0
4 years ago
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