The distance from the center of dilation, P, to.the image vertice S' is; 6 units.
<h3>What is the distance from the center of dilation, P, to the image S'?</h3>
It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.
Hence, since the dilation factor as given in the task content is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6units.
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Redued by 15%
orignal=100%
decrease by 15%=100%-15%=85%
find 85% of original
orignal=15 feet
85% of 15=0.85 times 15=12.75 feet
answer is B
Answer:
110
Step-by-step explanation:
for this problem you need to multiply the daily meals by 7(for each day of the week) getting a grand total of 112 meals per week. since the last digit is under 4, you round down so your final answer is 110
Answer:
x = 25% percent decrease
Step-by-step explanation:
For this problem we will use percentage calculation and make proportion:
Initial value 56 points is worth 100%
Second value 56 - 42 = 14 points of decrease is worth x%
56 : 14 = 100 : x
When we multiply external and internal members we get:
56 · x = 14 · 100 => x = 1400/56 = 25%
x = 25% percent decrease
God with you!!!
