The potential energy of the egg when it begins to fall is equal to the kinetic energy of the egg just before touching the ground:
m * g * h = (1/2) * m * v ^ 2
Clearing the speed:
v = root (2 * h * g)
Substituting the values
v = root (2 * (10) * (9.8)) = 14
Then, by definition, we have
F * deltat = m * deltav
Clearing F
F = (m * deltav) / (deltat)
Substituting the values
F = ((0.060) * (14)) / (2) = 0.42
answer
the force exerted on the egg by the floor was 0.42N
Answer:
(a)0.625s (b)1.569s
Explanation:
a.The ball reaches its maximum height when its speed = 0, or changing from positive to negative. To find out the time t for this we need to get the velocity function by taking the first derivative of the height function:
So when v(t) = 0
b. The ball land back on the ground when s(t) = 0:
Answer:14.14 cm
Explanation:
Given
Spring Compression
Potential energy Stored in spring
Suppose k is the spring constant of spring
Potential Energy of spring is given by
for 100 J energy
Answer:
The magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force. ( ¹/₄ F)
Explanation:
The electrostatic force between two charges is given by Coulomb's law;
where;
Q₁ and Q₂ are the magnitude of the charges
r is the distance between the charges
k is Coulomb's constant
Since the charges are identical;
Q₁ = Q
Q₂ = Q
the electrostatic force experienced by each charge is given by;
When each of the spheres has lost half of its initial charge;
Q₁ = Q/2
Q₂ = Q/2
Therefore, the magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force.