3 years ago

An 6 kg object accelerating from 17 m/s to 10 m/s. What is the change in momentum of the object?

Physics

1 answer:

Oksana_A [137]3 years ago

3 0

Answer:

the change is = 17 × 10 = 170 =28.33

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$\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow \\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{3.3\times 10^{-2}\times 10.8^2}{125}}\\\Rightarrow A=0.17547\ m$

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hope this helps you

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There is a 50 g sample of Ra-229. It has a half-life of 4 minutes.

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