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DanielleElmas [232]
3 years ago
13

An 6 kg object accelerating from 17 m/s to 10 m/s. What is the change in momentum of the object?

Physics
1 answer:
Oksana_A [137]3 years ago
3 0

Answer:

the change is = 17 × 10 = <u>1</u><u>7</u><u>0</u><u> </u>=28.33

6

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John, paul, and george are standing in a strawberry field. paul is 14.0 m due west of john. george is 36.0 m from paul, in a dir
sdas [7]

Position of paul with respect to john is given as

14 m due west of john

r_{pj} = r_p - r_j = -14\hat i

position of George with respect to Paul is given as 36 m in direction 37 degree south of east

r_{GP} = r_G - r_p = 36cos37\hat i - 36 sin37\hat j

now we need to find the position of George with respect to John

r_{GJ} = r_G - r_j[\tex]now for the above equation we can add the two equations[tex]r_{Gj} = -14\hat i + 36 cos37\hat i - 36sin37\hat j

r_{Gj} = 14.75\hat i - 21.67\hat j

so the magnitude is given as

r = \sqrt{14.75^2 + 21.67^2} = 26.2 m

and direction is given as

\theta = tan^{-1}\frac{21.67}{14.75}= 55.75 degree

<em>so it is 26.2 m at an angle 55.75 degree South of east</em>

7 0
3 years ago
Read 2 more answers
How is work affected when an object is lifted straight up instead of using a ramp? Work will increase.
kifflom [539]
Without friction, the amount of work only depends on the final height,
and is not affected by the route used to get there. 

If the ramp has no friction, then it has no effect on the total amount
of work done.  The work to lift the load straight up is the same.

If the ramp has some friction, then it takes more work to use the ramp
than to lift the load straight up.  Then the work to lift the load straight up
would be less than when the ramp is used.


3 0
3 years ago
What happens to the car if it is traveling in a circular path suddenly encounters ice?
pychu [463]

the car's friction is reduced to zero

the car's centripetal force drops to zero

the car continues in a straight path from the point at which it encountered the ice

8 0
3 years ago
Read 2 more answers
In 2000, a 20-year-old astronaut left Earth to explore the galaxy; her spaceship travels at 2.5 x 10^8 m/s. She returns in 2040.
lina2011 [118]

Answer:

42.11 years old

Explanation:

Given that:

In 2000, a 20-year-old astronaut left Earth to explore the galaxy; her spaceship travels at 2.5 x 10^8 m/s. She returns in 2040

To find her age we use:

\Delta t_m=\frac{\Delta t_s}{\sqrt{1-\frac{v^2}{c^2} } }\\

Δtm is  time interval for the observer stationary relative to the sequence of

events = 2040 - 2000 = 40 years

Δts is is the time interval for an observer moving with a speed v relative to the  sequence of event

v = velocity = 2.5 x 10^8 m/s

c = speed of light = 3 x 10^8 m/s

\Delta t_s=\Delta t_m}{\sqrt{1-\frac{v^2}{c^2} } }\\\Delta t_s=40\sqrt{1-\frac{(2.5*10^8)^2}{(3*10^8)^2}}\\\Delta t_s=22.11\ yr

Here age in 2000 is 20 year, therefore when she appear she would be 20 year + 22.11 year = 42.11 years old

7 0
3 years ago
A car is rounding a circular curve of radius r on a banked turn. As the drawing indicates, there are two forces acting on the ca
katovenus [111]

Answer:

The centripetal force is provided by the x component of the Normal Force.

Explanation:

The centripetal force is a force that makes something to follow a cicular trayectory, this force is always oriented to the center of the circunferency-

So you can see in the image that i attached there is only two forces actting on the car, the normal force and the weigth, and as you can see the y component of the normal force cancels with the weigth, but the x component of the normal force (as it has nothing to cancel with) makes the car follow the circular trayectory so this is the centripetal force.

6 0
4 years ago
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