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Mrrafil [7]
3 years ago
15

Noah drops a rock with a density of 1.73 g/cm3 into a pond. Will the rock float or sink? Explain your answer

Physics
2 answers:
denis-greek [22]3 years ago
8 0

Answer:

sink

Explanation:

brainly plz :(

stealth61 [152]3 years ago
4 0

Answer:

Sink

Explanation:

Water has a density of 1 g/cm³.  Since the density of the rock is greater than the density of water, the rock will sink.

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11–8 Consider a heavy car submerged in water in a lake with a flat bottom. The driver’s side door of the car is 1.1 m high and 0
Greeley [361]

Answer:

Explanation:

position of centre of mass of door from surface of water

= 10 + 1.1 / 2

= 10.55 m

Pressure on centre of mass

atmospheric pressure + pressure due to water column

10 ⁵ + hdg

= 10⁵ + 10.55 x 1000 x 9.8

= 2.0339 x 10⁵ Pa

the net force acting on the door (normal to its surface)

= pressure at the centre x area of the door

= .9 x 1.1 x 2.0339 x 10⁵

= 2.01356 x 10⁵ N

pressure centre will be at 10.55 m below the surface.

When the car is filled with air or  it is filled with water , in both the cases pressure centre will lie at the centre of the car .

7 0
3 years ago
A 320 g air track cart traveling at 1.25 m/s collides with a stationary 270 g cart. What is the speed of the 270 g cart after th
Nutka1998 [239]

Answer:

The speed of the 270g cart after the collision is 0.68m/s

Explanation:

Mass of air track cart (m1) = 320g

Initial velocity (u1) = 1.25m/s

Mass of stationary cart (m2) = 270g

Velocity after collision (V) = m1u1/(m1+m2) = 320×1.25/(320+270) = 400/590 = 0.68m/s

7 0
3 years ago
To display the New Document dialog box, click the Office Button and then click New.
UNO [17]
True clicking the office button and then clicking new would display the new document.

5 0
3 years ago
What would be the current of the same wire if it was moved up towards the magnet instead of through the magnetic field?
Aleks04 [339]

Answer:

0 v

Explanation:

3 0
3 years ago
You then measure Polly's internal temperature to be 13oC, which is quite a drop from the normal human body temperature of 37oC.
ankoles [38]

Answer:

The specific heat is 3.47222 J/kg°C.

Explanation:

Given that,

Temperature = 13°C

Temperature = 37°C

Mass = 60 Kg

Energy = 5000 J

We need to calculate the specific heat

Using formula of energy

Q= mc\Delta T

c =\dfrac{Q}{m\Delta T}

Put the value into the formula

c=\dfrac{5000}{60\times(37-13)}

c=3.47222\ J/kg^{\circ}C

Hence, The specific heat is 3.47222 J/kg°C.

5 0
3 years ago
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