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Nitella [24]
3 years ago
10

Josh has a toy car of mass 3 kg tied to a string of length 2 m. He ties the string to a pole and has the toy car drive in a circ

le around the pole at a speed of 3 m/s.
a. What is the centripetal acceleration of the car?

b. If the tension in the string exceeds 50 N, the string will break. How fast can he make the car go without breaking the string?
Physics
2 answers:
gulaghasi [49]3 years ago
5 0

Part a)

Centripetal acceleration is defined as

a_c = \frac{v^2}{R}

now here we know that

v = 3m/s

R = 2 m

m = 3 kg

now from above formula we have

a_c = \frac{3^2}{2}

a_c = 4.5 m/s^2

Part b)

Maximum possible tension in the string is given as

T = 50 N

now by force equation we have

F = ma

50 = 3 a

a = \frac{50}{3} m/s^2

now again by above formula

\frac{v^2}{R} = \frac{50}{3}

v = \sqrt{\frac{50 \times 2}{3}}

v = 5.77 m/s

aliina [53]3 years ago
5 0

a) a=v^2/R=4.5 m/s/s

b) F=ma=mv^2/R, so

v=\sqrt{FR/m}=5.77 m/s

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