Distributed Denial of Service /<span> </span><span>DDoS</span>
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Hope this is what you were looking for :)
Not sure what quizScore1-5 is, but here it is. Also, I'm not entirely sure what language you're working with here, but null can't be returned as an integer. If it were a string, for example, it'd be possible as string is an object reference type.
public int getData(int dataNumber)
{
if (dataNumber == 1)
return quizScore1;
else if (dataNumber == 2)
return quizScore2;
else if (dataNumber == 3)
return quizScore3;
else if (dataNumber == 4)
return quizScore4;
else if (dataNumber == 5)
return quizScore5;
else
return 0;
}
In the C programming language, you can't determine the array size from the parameter, so you have to pass it in as an extra parameter. The solution could be:
#include <stdio.h>
void swaparrayends(int arr[], int nrElements)
{
int temp = arr[0];
arr[0] = arr[nrElements - 1];
arr[nrElements - 1] = temp;
}
void main()
{
int i;
int myArray[] = { 1,2,3,4,5 };
int nrElements = sizeof(myArray) / sizeof(myArray[0]);
swaparrayends(myArray, nrElements);
for (i = 0; i < nrElements; i++)
{
printf("%d ", myArray[i]);
}
getchar();
}
In higher languages like C# it becomes much simpler:
static void Main(string[] args)
{
int[] myArray = {1, 2, 3, 4, 5};
swaparrayends(myArray);
foreach (var el in myArray)
{
Console.Write(el + " ");
}
Console.ReadLine();
}
static void swaparrayends(int[] arr)
{
int temp = arr[0];
arr[0] = arr.Last();
arr[arr.Length - 1] = temp;
}
