If A, B and C are collinear, then
1) if B is between A and C:
AC = AB + BC
AC = 48 + 22 = 70
2) if C is between A and B:
AB = AC + BC
48 = AC + 22 |-22
AC = 26
3) if A is between B and C:
BC = AB + AC
22 = 48 + AC |-48
AC = - 26 < 0 FALSE
Answer:
if B is between A and C, then AC = 70
if C is between A and B, then AC = 26
Answer: 350 adult tickets
Step-by-step explanation:
(omg I remember this question!)
- a stands for the number of adult tickets sold
student tickets : a + 65
<em>the equation for the prob: </em>
765 = a + (a + 65)
<em>solve:</em>
combine 'like terms'
1.) 765 = a + a + 65
2.) 765 = 2a + 65
<u>- 65 - 65 </u>
700= 2a
divide by 2
700/2 = 2a/2
<em>(700/2 = 350) </em>
<em>(the "2" in 2a is cancelled out by the other 2)</em>
<u>350 = a </u>
NO It can not!
Reason: the reason is because since both are the same , it will equal the mostly 0! So it wouldn’t make sense. So no!
Hoped I help mark brainly it would help me a lot!
There is only one change of sign, so there is only one possible positive root.
There are five changes of signs, so there are 5,3 or 1 possible negative roots.
The number of complex roots can be equal to 4,2 or 0 (degree of a polynomial - possible positive roots - possible negative roots)
