Perfect squares are:
1,4,9,16,25,36,49,64,81,100,....

the sum of the digits of our biggest number is 16 so any perfect square bigger than 16 doesn't work for us
1-
1+0=1 so any number containing the digits will work(keep in mind we only will look into whole numbers because digits can't be negative or have fractions or be irrational)
thereful 10 works for our category
2-
0+4=4
1+3=4
2+2=4
22 13 31 and 40 will work two
3-
0+9
1+8
2+7
3+6
4+5
90 18 81 27 72 36 63 45 54
4-
0+16
1+15
2+14
3+13
4+12
5+11
6+10
7+9
8+8
79 97 88

so our set of numbers contain:
10 22 13 31 40 90 18 81 27 72 36 63 45 54 79 97 88

3 0

3 years ago

If y varies directly as x squared and y = 72 when x =3, what is the value of y when x = 6? a. 18 b. 24 c. 288 d. 144 Please sele

kobusy [5.1K]

Answer:

it b why becaus

Step-by-step explanation:

7 0

3 years ago

Solve each of the following systems of equations by substitution

Delvig [45]

Answer:

1) The solution to the given equations is (3,6)

2) The solution to the given equations is (7,-1)

3) The solution to the given equations is (6,5)

Step-by-step explanation:

1) Given equations are $x+y=5\hfill (1)$

and $x=1+y\hfill (2)$

To solve the given equations by substitution method :

From equation (2) we have the value x=1+y

Substitute the value of x=1+y in equation (1) we get

(1+y)+y=5

1+y+y=5

1+2y=5

2y=5-1

2y=4

$y=\frac{4}{2}$

Therefore y=2

Now substitute the value of y=2 in equation (2) we get

x=1+y

x=1+2

Therefore x=3

The solution is (3,6)

2) Given equations are $2x+3y=11\hfill (1)$

and $x+y=6\hfill (2)$

To solve the given equations by substitution method :

From equation (2) we have the value x=6-y

Substitute the value of x=6-y in equation (1) we get

2(6-y)+3y=11

12-2y+3y=11

y=11-12

Therefore y=-1

Now substitute the value of y=-1 in equation (2) we get

x+(-1)=6

x=6+1

Therefore x=7

The solution is (7,-1)

3) Given equations are $x-y=1\hfill (1)$

and $6x-7y=1\hfill (2)$

To solve the given equations by substitution method :

From equation (1) we have the value x=1+y

Substitute the value of x=1+y in equation (2) we get

6(1+y)-7y=1

6+6y-7y=1

-y=1-6

Therefore y=5

Now substitute the value of y=5 in equation (1) we get

x-5=1

x=1+5

Therefore x=6

The solution is (6,5)

8 0

3 years ago

HELP ME PLZ

Doss [256]

B,D, E
B because 11*26=286 and 1*11=11
D because 5*26=130 and 1*5=5
E because 26*.25=6.5 and 1*.25=.25
It isnt a or c because 1:26 does not equal 26:1

4 0

3 years ago