Answer:
sin O = 
Step-by-step explanation:
given tan O =
= 
Then this is a right triangle with legs 3 and 4
Using Pythagoras' identity then the hypotenuse (h ) is
h =
=
= 5, hence
sin O =
= 
Answer:
Option B.
Step-by-step explanation:
It is given that ΔSRQ is a right angle triangle, ∠SRQ is right angle.
RT is altitude on side SQ, ST=9, TQ=16 and SR=x.
In ΔSRQ and ΔSTR,
(Reflexive property)
(Right angle)
By AA property of similarity,

Corresponding parts of similar triangles are proportional.

Substitute the given values.


On cross multiplication we get


Taking square root on both sides.


The value of x is 15. Therefore, the correct option is B.
We want to find h and k so that
3x³ - 6x² + 4x - 2 ≡ (x-2)(3x² + hx + 4) + k
Expand the right side.
(x-2)(3x² + hx + 4) + k
= 3x³ + hx² + 4x - 6x² - 2hx - 8 + k
= 3x³ + (h-6)x² + (4 - 2h)x + k - 8
Match coefficients of x²:
h - 6 = -6
h = 0
Match coefficients of x:
4 - 2h = 4 (Correct because h=0)
Match constants.
k - 8 = -2
k = 6
Answer: h=0, k=6
6y-8
6y is 6 times y
-8 is 8 less