Question

Brand X sells 21 oz. Bags of mixed nuts that contain 29% peanuts. To make their product they combine brand A mixed nuts which contain 35% peanuts and brand B mixed nuts which contain 25% peanuts. How much of each do they need to use

Answer 1

Answer:

Brand X has to mix 8.4 oz of brand A mixed nuts which contain 35% peanuts and 12.6 oz of brand B mixed nuts which contain 25%, to obtain 21 oz. Bags of mixed nuts that contain 29% peanuts.

Step-by-step explanation:

Hi

We define

$B_{A}=1oz @ 35\%$, wich means Brand A has 1 oz containing 35% peanuts.

$B_{B}=1oz @ 25\%$, wich means Brand b has 1 oz containing 25% peanuts.

So we can build an equiation system

(1) $B_{a}+B_{b}=21$

(2)$0.35 \times B_{a}+0.25 \times B_{b}=0.29 \times 21$, after fixing it a little

(2)$0.35B_{a}+0.25B_{b}=6.09$

As we can use any method to solve the system, I used a calculator wich thrown the following results $B_{a}=8.4 \ oz$ and $B_{b}=12.6 \ oz$.