What is the smallest odd number with four different prime factors?
2 answers:
Obviously the smallest odd number we are looking for will have the SMALLEST four prime factors.
The smallest four prime numbers are 2,3,5,7. The lowest multiple of this is 2*3*5*7 = 210 But this is an even number!
So let's remove 2, and use the next prime number: 3,5,7,11. The lowest multiple of these is 3*5*7*11 = 1155.
The answer is 210 since the numbers are (2x3x5x7)
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Answer:
Y = -X - 7
Step-by-step explanation:
y-y1 =m(x-x1)
y-(-2)= -1(x-(-5)
y+2 = -1(x+5)
Solve for y
subtract 2 from both sides
y=-x-5-2
Y = -x-7
(x-6) (x-2) is our factored answer
Answer:
5/2
Step-by-step explanation:
(18/15)*(25/12)=(18*25)/(15*12)=450/180=5/2
Answer: x=15
Step-by-step explanation:
15×2=30+6=36
The answer to your question is,
27,000.
70,000 minus 43,000 equals 27,000.
-Mabel <3
