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3 years ago

What is the smallest odd number with four different prime factors?

2 answers:

8 0

Obviously the smallest odd number we are looking for will have the SMALLEST four prime factors.

The smallest four prime numbers are 2,3,5,7. The lowest multiple of this is 2*3*5*7 = 210 But this is an even number!

So let's remove 2, and use the next prime number: 3,5,7,11. The lowest multiple of these is 3*5*7*11 = 1155.

torisob [31]3 years ago

5 0

The answer is 210 since the numbers are (2x3x5x7)

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A skydiver is falling at about 176 feet per second. How many feet per minute?

bixtya [17]

176 feet per sec × 6o secs in a minute = 10560

3 0

3 years ago

suppose that the lifetime of a transistor is a gamma random variable x with mean of 24 weeks and standard deviation of 12 weeks.

emmainna [20.7K]

The probability that the transistor will last between 12 and 24 weeks is 0.424

X= lifetime of the transistor in weeks E(X)= 24 weeks

O,= 12 weeks

The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.

X~gamma( $\alpha ,\beta$ )

E(X)= $\alpha \beta$ $\beta$ = $12^{2}/24$ =6 weeks

V(x)= $\alpha \beta ^{2}$ $\alpha$ =24/6= 4

Now we can find the solutions:

The excel formula used to create Figure one is as follows:

=gammadist(X, $\alpha$ , $\beta$ , False)

P( $12\leq X\leq 24$ )

P( $12/6\leq G\leq 24/6$ )

P( $2\leq G\leq 4$ )

P= 0.424

Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424

To learn more about probability click here:

brainly.com/question/11234923

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4 0

1 year ago

Read 2 more answers

Find the area of the circle. 12 ft

Ratling [72]

Answer:

Area of the circle is 113.04 ft²

Step-by-step explanation:

Given:

Diameter of circle = 12 feet

To Find:

Area of the circle

Using formula:

$\\ \: \: \dashrightarrow \: \: \:{\underline{\boxed{ \bf{Area_{( circle)} = \pi r^2}}}} \\ \\$

Where,

π = 3.14
Diameter = 12 feet
Radius = 12/2 = 6 feet

On substituting the required values, we get:

$\\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 3.14 \times {(6)}^{2} \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 3.14 \times 36 \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 113.04 \: {ft}^{2} \\ \\ \\$