Answer: he did travel 15 meters.
Explanation:
We have the data:
Acceleration = a = 1.2 m/s^2
Time lapes = 3 seconds
Initial speed = 3.2 m/s.
Then we start writing the acceleration:
a(t) = 1.2 m/s^2
now for the velocity, we integrate over time:
v(t) = (1.2 m/s^2)*t + v0
with v0 = 3.2 m/s
v(t) = (1.2 m/s^2)*t + 3.2 m/s
For the position, we integrate again.
p(t) = (1/2)*(1.2 m/s^2)*t^2 + 3.2m/s*t + p0
Because we want to know the displacementin those 3 seconds ( p(3s) - p(0s)) we can use p0 = 0m
Then the displacement at t = 3s will be equal to p(3s).
p(3s) = (1/2)*(1.2 m/s^2)*(3s)^2 + 3.2m/s*3s = 15m
Answer:
The time is 0.5 sec.
Explanation:
Given that,
Voltage V= 12.00 V
Inductance L= 1.20 H
Current = 3.00 A
Increases rate = 8.00 A
We need to calculate change in current

We need to calculate the time interval
Using formula of inductor


Where,
= change in current
V = voltage
L = inductance
Put the value into the formula


Hence, The time is 0.5 sec.
Answer: 115.2kg
Explanation:
Net force = 265 N
Acceleration of bike & rider = 2.30m/s2 (The SI unit of acceleration is m/s2)
Mass of the bike and rider together = ?
Since force is the product of the mass of an object and the acceleration by which it moves, Force = Mass x Acceleration
265N = Mass x 2.30m/s2
Mass = (265N/2.30m/s2)
Mass = 115.2 kg
Thus, the Mass of the bike and rider together is 115.2kg
Answer:
0.0034 sec
Explanation:
L = initial length
T = initial time period = 2.51 s
Time period is given as


L = 1.56392 m
L' = new length
ΔT = Rise in temperature = 142 °C
α = coefficient of linear expansion = 19 x 10⁻⁶ °C
New length due to rise of temperature is given as
L' = L + LαΔT
L' = 1.56392 + (1.56392) (19 x 10⁻⁶) (142)
L' = 1.56814 m
T' = New time period
New time period is given as


T' = 2.5134 sec
Change in time period is given as
ΔT = T' - T
ΔT = 2.5134 - 2.51
ΔT = 0.0034 sec