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Elza [17]
4 years ago
11

A= v50cm-v20cm __________________ t

Physics
1 answer:
Degger [83]4 years ago
8 0

Answer:

Explanation:

a= v50cm-v20cm

__________________

t

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3 years ago
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Question 9 Unsaved A 680-Hz sound wave travels at 340 m/s in air, with a wavelength of 0.5 m. 5 m. 50 m. 500 m. none of the abov
ale4655 [162]

The correct option is 0.5 M

Calculation

Wavelength is defined as the ratio of velocity of a wave to its frequency. It is measure in meters. Mathematically, wavelength is given by the following formula:

Wavelength = wave velocity / frequency

From the details given in the question,

Wavelength =?

Velocity = 340 m/s

Frequency = 680 HZ

Wavelength = 340 /680 = 0.5

Therefore, wavelength = 0.5 M

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3 years ago
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Is a body which is moving in a negative direction but has a positive acceleration speeding up or slowing down?​
melamori03 [73]

Answer:

An object with negative acceleration could be speeding up, and an object with positive acceleration could be slowing down.

Explanation:

hope this helps

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7 0
3 years ago
What is kinematics??? explain!!!​
posledela

Answer:

Kinematics is the study of motion of a system of bodies without directly considering the forces or potential fields affecting the motion. In other words, kinematics examines how the momentum and energy are shared among interacting bodies.

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3 years ago
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1.A car starts from rest and acquires a velocity of 54 km/h in 2 minutes.Find(i) the acceleration and(ii) distance travelled by
Sergeu [11.5K]

Answer:

1.) 1620 km/h^2

2.) 2.7 km

Explanation:

1.) Given that the car start from rest. The initial velocity U will be equal to zero. That is,

U = 0.

Final velocity V = 54 km/h

Time t = 2 minute = 2/60 = 1/30 hour

Acceleration a will be change in velocity per time taken. That is,

a = ( V - U )/ t

Substitute V, U and t into the formula

a = 54 ÷ 1/30

a = 54 × 30 = 1620 km/h ^2

2.) Distance travelled S by the car during the time can be calculated by using the 2nd equation of motion.

S = Ut + 1/2at^2

Substitute all the parameters into the formula

S = 54 × 1/30 + 1/2 × 1620 × (1/30)^2

S = 54/30 + 810 × 1/900

S = 54/30 + 810/900

S = (1620+810)/900

S = 2430/900

S = 2.7 km.

Therefore, distance travelled by the car during this time is 2.7 km

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3 years ago
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