A frictional torque is exerted on a platform while it rotates because the force is along it's axis and changes only the magnitude and not the direction of the angular velocity.
<h3>What is frictional torque?</h3>
A frictional torque is a rotational force that is caused by the movement of two objects that are in contact.
To collect data needed to find the frictional torque exerted on the platform while it rotates the experimental procedure the student should use include the following:
- A disc shaped platform with know inertia
- The platform should be mounted on a fixed axle.
- The platform should also be rotating on a horizontal plane.
The quantities that should be measured is that rotational frictional force and angular velocity.
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Infrared waves are ineffective for treating cancer because they do not transfer enough energy to destroy cancer cells.
<h3>Importance of high frequency waves</h3>
One of the uses of a high frequency wave is in the treatment of cancer. These high frequency waves transfer enough energy to destroy the cancer cells.
E = hf
where;
- f is frequency of the wave
Infrareds have low frequency, and hence low energy.
Thus, infrared waves are ineffective for treating cancer because they do not transfer enough energy to destroy cancer cells.
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Explanation:
the force exerted from by the car on the wall Is contact force
the force exerted by the wall on the car i don't know
Answer:
there is no net force acting on the object
Explanation:
If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).
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Answer:
20 mm
Explanation:
First, we calculate the velocity with which the object is released.
So, elastic potential energy = kinetic energy
1/2kx² = 1/2mv²
v = √(k/m)x where k = spring constant = 2000 N/m, m = mass = 0.3 kg and x = 0.04 m
v = √(2000 N/m/0.3 kg)0.04 m
v = 81.65 × 0.04 m
v = 3.27 m/s
We then calculate its acceleration, a from
F = kx = ma
a = kx/m
= 2000 N/m × 0.04 m/0.3 kg = 266.67 m/s²
We now calculate the height, h moved from v² = u² + 2ah where u = initial velocity = 3.27 m/s, v = final velocity at height, h = 0 (since it will be stationary) a = -266.67 m/s² (since its velocity is decreasing)
v² = u² + 2ah
0 = (3.27 m/s)² + 2 ×-266.67h
-10.693 = -533.34h
h = -10.693/533.34 = 0.020 m = 20 mm