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givi [52]
3 years ago
14

Given l(-4,3) and m(-7,-2), what's the length of lm

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0
Distance = Square Root ( (X difference)^2<span> + (Y difference)^</span>2<span> )
</span>
Distance = Square Root ( (-4 --7)^2 + ( 3 --2)^2<span> )

</span>Distance = Square Root (3^2 + 5^2)

<span>Distance = Square Root (9 + 25)

Distance = </span><span>Square Root (34)

Distance = </span><span>5.8309518948

Therefore the length of lm equals </span> <span> <span> <span> 5.8309518948 </span> </span> </span>


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Part B 200 - 80 = 120

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5 0
3 years ago
What is the sum of 12 – 5i and –3 + 4i?<br> –16 + 63i <br>9 – i <br>9 – 9i <br>15 – 9i
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Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{9 - i}}}}}

Step-by-step explanation:

\sf{12 - 5i + ( - 3 + 4i)}

When there is a ( + ) in front of an expression in parentheses, there is no need to change the sign of each term. That means, the expression remains the same. Just remove the parentheses

\longrightarrow{ \sf{12 - 5i - 3 + 4i}}

Collect like terms

\longrightarrow{ \sf{ 12 - 3 - 5i + 4i}}

Subtract 3 from 12

\longrightarrow{ \sf{9 - 5i + 4i}}

Collect like terms

\longrightarrow{ \sf{9 - i}}

Hope I helped!

Best regards! :D

3 0
3 years ago
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Varvara68 [4.7K]

Answer:

The center of circle is (0,0)

Step-by-step explanation:

We need to find the center of the circle of the equation x^{2}+y^{2}=4

Since, the general equation of circle is (x-h)^{2}+(y-k)^{2} = r^{2}

Where (h,k) is center of circle and r is radius.

Re-write the circle equation is x^{2}+y^{2}=4 as,

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Compare x^{2}+y^{2}=2^{2} with (x-h)^{2}+(y-k)^{2} = r^{2}

so, (x-0)^{2}+(y-0)^{2} = 2^{2}

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4 0
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Answer:

80 %

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MrRa [10]

Answer:24/34

Step-by-step explanation:

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4 years ago
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