Question

Find the center of the circle whose equation is x² + y² = 4.

Answer 1

Answer:

The center of circle is $(0,0)$

Step-by-step explanation:

We need to find the center of the circle of the equation $x^{2}+y^{2}=4$

Since, the general equation of circle is $(x-h)^{2}+(y-k)^{2} = r^{2}$

Where (h,k) is center of circle and r is radius.

Re-write the circle equation is $x^{2}+y^{2}=4$ as,

$x^{2}+y^{2}=2^{2}$

Compare $x^{2}+y^{2}=2^{2}$ with $(x-h)^{2}+(y-k)^{2} = r^{2}$

so, $(x-0)^{2}+(y-0)^{2} = 2^{2}$

Hence, the center of circle is $(0,0)$

Answer 2

Since the center of the circle is represented by whatever numbers are being subtracted by x and y, and there are no numbers tagged to x and y, your center is the origin, or (0,0).