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PolarNik [594]
3 years ago
7

A piston is filled with gas. When the pressure is increasing, what is happening to the volume? Assume that all other properties

of the gas remain constant.
a. It is remaining the same.
b. It is increasing.
c. It is decreasing.
d. It is increasing or decreasing until it reaches zero.
Physics
1 answer:
Kryger [21]3 years ago
3 0
The correct answer is letter C. Volume is decreasing. For a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume<span> are </span>inversely proportional<span>. </span>
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FinnZ [79.3K]

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The gunner must apply 240 N  to the gun to stop it from moving back.

Explanation:

6 0
3 years ago
Warm air rises because it has less ___________.
REY [17]

Answer:

because it is less dense than the surrounding air

Explanation:

5 0
3 years ago
Ring of mass straight m and radius straight r is attached to the end of a thin rod of mass straight m and radius 2 straight r
Katen [24]

The total moment of inertia about an axis is : L^{2} ( \frac{M}{3} + m ) + \frac{2mr^2}{5} for a ring of mass m and radius straight r attached to a thin rod.

<h3>Determine the Total moment of Inertia about an axis </h3>

<u>Given data:</u>

mass of ring --> m

radius of ring --> r

mass of rod --> M

Length of rod ---> L ( 2 * radius )

Total Moment of Inertia about an axis = Irod  +  Iring

where : Irod = moment of inertia of rod,  Iring = moment of inertia of ring

Irod = ML² / 3

Iring = 2mr² / 5

moment of inertia around an axis by Iring = I

where ;  I = 2mr² / 5  + ML²   according to parallel axis theorem

Hence the Total moment of Inertia about an axis is :

Itotal =  2mr²/5  +  ML²  +  ML² / 3

        = L^{2} ( \frac{M}{3} + m ) + \frac{2mr^2}{5}

 

Learn more about Moment of inertia : brainly.com/question/6956628

4 0
3 years ago
Read 2 more answers
An aircraft, traveling northward, lands on a runway with a speed of 77 m/s. Once it touches down, it slows to 6.3 m/s over 705 m
KengaRu [80]

Answer:

magnitude

a = 4.18 m/s^2

Direction

Opposite to the velocity of aircraft

Explanation:

As we know that the initial speed of the aircraft when it land on the ground is

v_i = 77 m/s

now the final speed of the aircraft when it covers 705 m on runway is given as

v_f = 6.3 m/s

so here we know that

v_f^2 - v_i^2 = 2 a d

so now we can say that

6.3^2 - 77^2 = 2ad

6.3^2 - 77^2 = 2(a)(705)

a = -4.18 m/s^2

5 0
3 years ago
As a box slides down a ramp, friction does 23.0 joules of work. At the bottom of the ramp, the box has 3.8 joules of kinetic ene
tensa zangetsu [6.8K]

Answer:

The high of the ramp is 2.81[m]

Explanation:

This is a problem where it applies energy conservation, that is part of the potential energy as it descends the block is transformed into kinetic energy.

If the bottom of the ramp is taken as a potential energy reference point, this point will have a potential energy value equal to zero.

We can find the mass of the box using the kinetic energy and the speed of the box at the bottom of the ramp.

E_{k}=0.5*m*v^{2}\\\\where:\\E_{k}=3.8[J]\\v = 2.8[m/s]\\m=\frac{E_{k}}{0.5*v^{2} } \\m=\frac{3.8}{0.5*2.8^{2} } \\m=0.969[kg]

Now applying the energy conservation theorem which tells us that the initial kinetic energy plus the work done and the potential energy is equal to the final kinetic energy of the body, we propose the following equation.

E_{p}+W_{f}=E_{k}\\where:\\E_{p}= potential energy [J]\\W_{f}=23[J]\\E_{k}=3.8[J]\\

And therefore

m*g*h + W_{f}=3.8\\ 0.969*9.81*h - 23= 3.8\\h = \frac{23+3.8}{0.969*9.81}\\ h = 2.81[m]

8 0
3 years ago
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