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Maru [420]
3 years ago
10

What are 5 hazards of static electricity?​

Physics
1 answer:
Lana71 [14]3 years ago
7 0

Answer:

It is dangerous when there are flammable gases or a high concentration of oxygen. A spark could ignite the gases and cause an explosion. It is dangerous when you touch something with a large electric charge on it. The charge will flow through your body causing an electric shock.

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Scorpion4ik [409]

Answer:

protect equipment by stopping the flow of electric current; protect your house from fire.

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Which of these forces could speed up a baseball?
kkurt [141]
B) Applied and gravitational forces
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Two electrons travel towards each other at 0.2 c parallel to the laboratory x-axis. What is the relative velocity of one electro
Leya [2.2K]

1) In the reference frame of one electron: 0.38c

To find the relative velocity of one electron with respect to the other, we must use the following formula:

u'=\frac{u-v}{1-\frac{uv}{c^2}}

where

u is the velocity of one electron

v is the velocity of the second electron

c is the speed of light

In this problem:

u = 0.2c

v = -0.2c (since the second electron is moving towards the first one, so in the opposite direction)

Substituting, we find:

u'=\frac{0.2c+0.2c}{1+\frac{(0.2c)(0.2c)}{c^2}}=\frac{0.4c}{1+0.04}=0.38c

2) In the reference frame of the laboratory: -0.2c and +0.2c

In this case, there is no calculation to be done. In fact, we are already given the speed of the two electrons; we are also told that they travel in opposite direction, so their velocities are

+0.2c

-0.2c

5 0
3 years ago
A car is running at a velocity of 50 miles per hour and the driver accelerates the car by 10 miles per hour square.How far the c
krek1111 [17]
It will be 80 miles and it can be done only in 16 min
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A uniform log of length L is inclined 30° from the horizontal when supported by a frictionless rock located 0.6L from its left e
mafiozo [28]

Answer:

x = 0.974 L

Explanation:

given,

length of inclination of log = 30°

mass of log = 200 Kg

rock is located at = 0.6 L

L is the length of the log

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let x be the distance from left at which log is horizontal.

For log to be horizontal system should be in equilibrium

 ∑ M = 0

mass of the log will be concentrated at the center  

distance of rock from CM of log = 0.1 L

now,

∑ M = 0

m_{log} g \times 0.1 L = m_{engineer} g \times (x - 0.6 L)

200 \times 0.1 L = 53.5 \times (x - 0.6 L)

0.374 L =x - 0.6 L

       x = 0.974 L

hence, distance of the engineer from the left side is equal to x = 0.974 L

7 0
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