Sulfur normally has 16 electrons (see the periodic table), but the 2- indicates that the atom is gaining 2 electrons. because of that, the answer would be 18.
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The answer is B) dry and irregular
The air escapes into the atmosphere.
An <em>emulsion</em> is a colloidal dispersion of one liquid in another liquid in which it does not dissolve.
<em>Ice cream</em> is essentially an emulsion of the fat in milk with a sugar solution trapped in a network of small ice crystals. Other chemicals are added to prevent the emulsion from separating, and air bubbles are mixed into the semisolid mixture.
<em>Up to 50 %</em> of the volume of ice cream can be air.
When the ice cream melts, the air bubbles are <em>no longer trapped</em>. They just escape into the atmosphere.
If you re-freeze the melted ice cream, its volume will be much less than the original.
Answer:
1a. Both sides of the decay reaction have the same charge.
b. The number of nucleons on both sides are the same.
2. The binding energy of one mole of the atom is 17.172 ×
J.
Explanation:
1a. Considering the two sides of the decay reaction and with respect to the law of conservation of charge, it can be observed that both sides have the same charge. Charge can not be created or destroyed in the process.
b. The number of nucleons on both sides are equal. No nucleon is created or destroyed in the process.
2. Binding energy is the minimum energy required to separate an atom into its nucleons. From Einstein's energy equation;
E = Δm
Where E is the binding energy of the atom, Δm is the mass defect and c is the speed of light.
Given that: Δm = 1.908 g/mol and c = 3 ×
. So that:
E = 1.908 × 
= 1.908 × 9 × 
= 17.172 ×
J
The binding energy of one mole of the atom is 17.172 ×
J.
Answer:
Explanation:
pH = pKa + log [ CH₃COO⁻ ] / [CH₃COOH ]
5.36 = 4.86 + log [ CH₃COO⁻ ] / [CH₃COOH ]
log [ CH₃COO⁻ ] / [CH₃COOH ] = .5
[ CH₃COO⁻ ] / [CH₃COOH ] = 3.16
moles of CH₃COOH = .680 x .9 = .612 M
Let x mole of KOH is required
x /( .612 - x ) = 3.16
x = 1.933 - 3.16 x
x = .46488
.46488 moles of KOH will be required
volume required be V
v x 2.62 = .46488
v = .1774 L
= 177.4 mL
177.4 mL of 2.62 M KOH will be required .