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Svetlanka [38]
4 years ago
10

Write a balanced net ionic equation for the following reaction. Explain how you arrived at this answer. What did you cancel out?

AgNO^3 (aq) + KCI (aq) ----> AgCI (s) + KNO^3 (aq)
Chemistry
1 answer:
yaroslaw [1]4 years ago
8 0

 The net ionic equation  is


Ag⁺(aq)  +Cl⁻(aq) →  AgCl(s)


Explanation


AgNO₃ (aq)  + KCl (aq)→ AgCl(s) +KNO₃(aq)



from above  molecular equation break  all  soluble electrolyte  into ions


Ag⁺(aq) +NO₃⁻ (aq) + K⁺(aq) +Cl⁻(aq) →   AgCl (s) + K⁺(aq) + No₃⁻(aq)



cancel the spectator  ions  in both side  of  equation =K⁺  and NO₃⁻  ions



The net  ionic equation is therefore


= Ag⁺(aq)  + Cl⁻(aq) →    AgCl(s)

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Which of the following description of the moons surface is accurate?
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What do you think happens to the air in the collid when ice cream melts ?
vichka [17]

The air escapes into the atmosphere.

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When the ice cream melts, the air bubbles are <em>no longer trapped</em>. They just escape into the atmosphere.

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6 0
3 years ago
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Use the nuclear decay reaction in the picture to answer the following question.
allsm [11]

Answer:

1a. Both sides of the decay reaction have the same charge.

b. The number of nucleons on both sides are the same.

2. The binding energy of one mole of the atom is 17.172 × 10^{16} J.

Explanation:

1a. Considering the two sides of the decay reaction and with respect to the law of conservation of charge, it can be observed that both sides have the same charge. Charge can not be created or destroyed in the process.

b. The number of nucleons on both sides are equal. No nucleon is created or destroyed in the process.

2. Binding energy is the minimum energy required to separate an atom into its nucleons. From Einstein's energy equation;

             E = Δmc^{2}

Where E is the binding energy of the atom, Δm is the mass defect and c is the speed of light.

Given that: Δm = 1.908 g/mol and c = 3 × 10^{8}. So that:

           E = 1.908 × (3*10^{8}) ^{2}

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The binding energy of one mole of the atom is 17.172 × 10^{16} J.

5 0
3 years ago
You need to prepare an acetate buffer of pH 5.36 from a 0.900 M acetic acid solution and a 2.62 M KOH solution. If you have 680
Alexus [3.1K]

Answer:

Explanation:

pH = pKa + log [ CH₃COO⁻ ] / [CH₃COOH ]

5.36 = 4.86 + log [ CH₃COO⁻ ] / [CH₃COOH ]

log [ CH₃COO⁻ ] / [CH₃COOH ]  = .5

[ CH₃COO⁻ ] / [CH₃COOH ]  = 3.16

moles of CH₃COOH = .680 x .9 = .612 M

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x /( .612 - x ) = 3.16

x = 1.933 - 3.16 x

x = .46488

.46488 moles of KOH will be required

volume required be V

v x 2.62 =  .46488

v = .1774 L

= 177.4 mL

177.4 mL  of  2.62 M KOH will be required .

6 0
3 years ago
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