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3 years ago

What volume of 0.220 M HBr solution (in mL) is required to obtain 0.060 moles of HBr?

Chemistry

1 answer:

soldi70 [24.7K]3 years ago

4 0

Answer:

273 mL.

Explanation:

From the question given above, the following data were obtained:

Molarity of HBr = 0.220 M

Mole of HBr = 0.060 mole

Volume =?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the volume required as illustrated below:

Molarity of HBr = 0.220 M

Mole of HBr = 0.060 mole

Volume =?

Molarity = mole /Volume

0.220 = 0.060 / Volume

Cross multiply

0.220 × Volume = 0.060

Divide both side by 0.220

Volume = 0.060 / 0.220

Volume = 0.273 L

Finally, we shall convert 0.273 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.273 L = 0.273 L × 1000 mL / 1 L

0.273 L = 273 mL

Thus, 0.273 L is equivalent to 273 mL.

From the calculations made above, 273 mL of HBr is required.

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Answer:

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Explanation:

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where a, b, c and d are the stoichiometric coefficients of compounds A, B, C and D, the equilibrium constant Kp is determined by the following expression:

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Where Px is the partial pressure of each of the components once equilibrium has been reached and they are expressed in atmospheres. The equilibrium constant Kp depends solely on temperature and is dimensionless.

In the case of the reaction:

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the equilibrium constant Kp is determined by the following expression:

$Kp=\frac{P_{H_{2} } *P_{I_{2} } }{P_{HI} ^{2} }$

The system comes to equilibrium at 425 °C, and

PHI = 0.794 atm
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Replacing:

$Kp=\frac{0.0685*0.0685}{0.794^{2} }$

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3 years ago

Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT

marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L = L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

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7 0

4 years ago

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Answer:

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Explanation:

Step 1: Given data

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The density (ρ) of a substance is equal to its mass divided by its volume.

ρ = m / V

ρ = 21.112 g / 19.5 cm³

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First of all, you have to translate the words into an equation.

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Finally it is the turn of the carbons. There are 3 on the right, so you must make the carbon on the left = 3

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5 0

4 years ago

What volume of 0.220 M HBr solution (in mL) is required to obtain 0.060 moles of HBr?​

What volume of 0.220 M HBr solution (in mL) is required to obtain 0.060 moles of HBr?