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lina2011 [118]
3 years ago
9

Help please please please

Mathematics
2 answers:
Olenka [21]3 years ago
7 0

Answer: the answer is x=30

Step-by-step explanation:

harkovskaia [24]3 years ago
6 0
The answer is x=30 I believe
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Graph f(x)=−3/4x−4 . Use the line tool and select two points to graph the line.
lions [1.4K]

Answer:

Two points on the line would be (0, -4) and (4, -7)

Step-by-step explanation:

In order to find this, we can start at the y-intercept. The y-intercept is the constant at the end of the equation. In this case it is -4, which gives us the first point of (0, -4).

We can find the second point by using the numerator of the slope to determine how much we go up or down (-3) and the denominator for how much we go left to right (4). So we add the 4 to the x value and add the -3 to the y value.

(4, -7)

3 0
3 years ago
Choose where it is a function or not a function also choose what is the range and the domain
kow [346]
Not a function because of the vertical line test.
Domain is [-2,∞] since the left most point is -2 and the right is unbounded.
Range is (-∞,∞) since it is not bounded in terms of y.
7 0
3 years ago
What's the distance between the points (0,9) and (7,7)?
Alexeev081 [22]
(7-9)^2+(0-7)^2
4+49
53^(1/2)
5 0
3 years ago
Calculate the Laplace transforms of the following from the definition. 1. y = t^2. y = t^3
Likurg_2 [28]

Answer:

1) L(y)=\frac{2}{s^{3}}

2) L(y)=\frac{6}{s^{4}}

Step-by-step explanation:

To find : Calculate the Laplace transforms of the following from the definition ?

Solution :

We know that,

Laplace transforms of t^n is given by,

L(t^n)=\frac{n!}{s^{n+1}}

1) y=t^2

Laplace of y,

L(y)=L(t^2) here n=2

L(y)=\frac{2!}{s^{2+1}}

L(y)=\frac{2}{s^{3}}

2) y=t^3

Laplace of y,

L(y)=L(t^3) here n=3

L(y)=\frac{3!}{s^{3+1}}

L(y)=\frac{3\times 2}{s^{4}}

L(y)=\frac{6}{s^{4}}

5 0
3 years ago
Select all the functions whose graphs include the point (3, 12)
anygoal [31]

1.   Y=4

2.  Y=2

3.  Y=X

4.  Y=2

(X,Y)

i hope this helps

Step-by-step explanation:

8 0
2 years ago
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