Iodine is prepared both in the laboratory and commercially by adding Cl2(g) to an aqueous solution containing sodium iodide: 2Na
I(aq) +Cl2(g) → I2(s) +2NaCl(aq) How many grams of iodide, NaI, must be used to produce 55.6 g of iodine, I2?
1 answer:
Answer: 65.7 gram
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of are produced by = 2 moles of
Thus 0.219 moles of will be produced by = of
Mass of
Thus 65.7 g of NaI, must be used to produce 55.6 g of iodine
You might be interested in
Answer:
is any thing which has mass volume and empty space
Answer:
1. Sodium Oxide
2. Barium Sulfide
3. Copper (II) sulfate
4. Mercury (II) chloride
5. Silver Nitrate
6. CuO
7. FeCl3
8. Zn (NO3)2
9. Mg (OH)2
10. SnS
Answer:
3H2 + N2 → 2NH3
Explanation:
3H2 + 1N2 → 2NH3
Or
3H2 + N2 → 2NH3
Answer:
1837:1
Explanation: