The asymptotes of the open loop transfer are:
- Horizontal: y = 0
- Vertical: x = -10 and x = -100
<h3>How to plot the
asymptotes?</h3>
The open loop transfer function is given as:
f(s) = 100(s + 1)/((s + 10)(s + 100))
Set the numerator of the function to 0.
So, we have:
f(s) = 0/((s + 10)(s + 100))
Evaluate
f(s) = 0
This means that, the vertical asymptote is y = 0
Set the denominator of the function to 0.
(s + 10)(s + 100) 0
Split
s + 10 = 0 and s + 100 = 0
Solve for s
s = -10 and s = -100
This means that, the horizontal asymptotes are s = -10 and s = -100
See attachment for the graph of the asymptotes
Read more about asymptotes at:
brainly.com/question/4084552
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Answer:
In Rankine 524.07°R
In kelvin 291 K
In Fahrenheit 64.4°F
Explanation:
We have given temperature 18°C
We have to convert this into Rankine R
From Celsius to Rankine we know that 
We have to convert 18°C
So 
Conversion from Celsius to kelvin
We have to convert 18°C

Conversion of Celsius to Fahrenheit
option 2 is your answer... thanks .. hope it helps
Answer:
<h2>No advantages bro!!</h2>
Explanation:
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