Answer:
I think it's 23 ohms.
Explanation:
Not entirely sure about it.
hope this helps
Answer:
When y = 0.25 ft, velocity gradient = -6 ft/s
When y = 0.5 f, velocity gradient = -1.5 ft/s
Explanation:
Given;
equation for the velocity profile, 3/2 = 4yv
Rearrange this equation, you will get;
![4yv = \frac{3}{2}\\\\v = \frac{3}{2} *\frac{1}{4y} \\\\v = \frac{3}{2}(\frac{1}{4} )(\frac{1}{y} )\\\\v = \frac{3}{8}y^{-1}\\\\ gradient \ of \ velocity \ = \frac{dv}{dy} \\\\\frac{dv}{dy} = -1(\frac{3}{8})y^{-2}](https://tex.z-dn.net/?f=4yv%20%3D%20%5Cfrac%7B3%7D%7B2%7D%5C%5C%5C%5Cv%20%3D%20%5Cfrac%7B3%7D%7B2%7D%20%2A%5Cfrac%7B1%7D%7B4y%7D%20%5C%5C%5C%5Cv%20%3D%20%5Cfrac%7B3%7D%7B2%7D%28%5Cfrac%7B1%7D%7B4%7D%20%29%28%5Cfrac%7B1%7D%7By%7D%20%29%5C%5C%5C%5Cv%20%3D%20%5Cfrac%7B3%7D%7B8%7Dy%5E%7B-1%7D%5C%5C%5C%5C%20gradient%20%5C%20of%20%5C%20velocity%20%5C%20%3D%20%5Cfrac%7Bdv%7D%7Bdy%7D%20%5C%5C%5C%5C%5Cfrac%7Bdv%7D%7Bdy%7D%20%3D%20-1%28%5Cfrac%7B3%7D%7B8%7D%29y%5E%7B-2%7D)
When y = 0.25 ft
![\frac{dv}{dy} = -1(\frac{3}{8})(0.25)^{-2}\\\\\frac{dv}{dy} = -6 \ ft/s](https://tex.z-dn.net/?f=%5Cfrac%7Bdv%7D%7Bdy%7D%20%3D%20-1%28%5Cfrac%7B3%7D%7B8%7D%29%280.25%29%5E%7B-2%7D%5C%5C%5C%5C%5Cfrac%7Bdv%7D%7Bdy%7D%20%3D%20-6%20%5C%20ft%2Fs)
When y = 0.5 ft
![\frac{dv}{dy} = -1(\frac{3}{8})(0.5)^{-2}\\\\\frac{dv}{dy} = -1.5 \ ft/s](https://tex.z-dn.net/?f=%5Cfrac%7Bdv%7D%7Bdy%7D%20%3D%20-1%28%5Cfrac%7B3%7D%7B8%7D%29%280.5%29%5E%7B-2%7D%5C%5C%5C%5C%5Cfrac%7Bdv%7D%7Bdy%7D%20%3D%20-1.5%20%5C%20ft%2Fs)
Answer:
![K_{I}=5.21 MPa\sqrt{m}](https://tex.z-dn.net/?f=K_%7BI%7D%3D5.21%20MPa%5Csqrt%7Bm%7D)
Explanation:
given data
Load P = 35 kN
Width of bar W = 50.8 mm
Breadth of bar B = 25 mm
Ratio of crack length to width α = a/W = 0.2
solution
we get here KI for a rectangular bar that is express as
................................1
here Y is the geometrical function
so
Y =
Y =
Y =
Y = 0.9878
so put here value in equation 1
![K_{I} = 165354.33\times 10^{3}\times 0.9878\times 0.0319](https://tex.z-dn.net/?f=K_%7BI%7D%20%3D%20165354.33%5Ctimes%2010%5E%7B3%7D%5Ctimes%200.9878%5Ctimes%200.0319)
= 5210.45 × 10³
= 5.21 MPa ![\sqrt{m}](https://tex.z-dn.net/?f=%5Csqrt%7Bm%7D)
Answer:
Dalton
The part of the close-out report that would describe how he would plan and manage projects in the future is:
summary of project management effectiveness
Explanation:
The Project Close-out Report is a project management document, which identifies the variances from the baseline plans. These variances are specified in terms of project performance, project cost, and schedule. The project close-out report records the completion of the project and the subsequent handover of project deliverables to others. The project management effectiveness summary details the project's objectives and the achievements recorded, including the lessons learned.