Answer:
Explanation:
public class Event
public final static int PRICE_PER_GUEST = 35;
public final static int CUT_OFF = 50;
//Attributes
private String eventNum;
private int noOfGuest;
private int price;
/**
* param eventNum the eventNum to set
*/
public void setEventNum(String eventNum)
this.eventNum = eventNum;
/**
* param noOfGuest the noOfGuest to set
*/
public void setNoOfGuest(int noOfGuest)
this.noOfGuest = noOfGuest;
this.price = this.noOfGuest * PRICE_PER_GUEST;
/**
* return the eventNum
*/
public String getEventNum()
return eventNum;
/**
* return the noOfGuest
*/
public int getNoOfGuest()
Answer:
The answer is "discipline" , I was doing the same thing a minute ago. I hope this anwser is helpful! ^^
Explanation:
Overcurrent protective devices, or OCPDs
Answer:
Using the above algorithm matches one pair of Ghostbuster and Ghost. On each side of the line formed by the pairing, the number of Ghostbusters and Ghosts are the same, so use the algorithm recursively on each side of the line to find pairings. The worst case is when, after each iteration, one side of the line contains no Ghostbusters or Ghosts. Then, we need n/2 total iterations to find pairings, giving us an P(
)- time algorithm.
