the other parallel side is 30 cm
Step-by-step explanation:
here's the solution :-
let the other parallel side be x
now,
=》Area of trapezium =
![\frac{1}{2} \times sum \: of \: parallel \: sides \times height =》[tex] \frac{1}{2} \times (x + 20) \times 16 = 400](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20sum%20%5C%3A%20of%20%5C%3A%20parallel%20%5C%3A%20sides%20%5Ctimes%20height%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3D%E3%80%8B%3C%2Fp%3E%3Cp%3E%5Btex%5D%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20%28x%20%2B%2020%29%20%5Ctimes%2016%20%3D%20400)
=》( x + 20 ) × 8 = 400
=》x + 20 = 400 ÷ 8
=》x = 50 - 20
=》x = 30
so length of other parallel side = x = 30 cm
1. 2 + 2.5x = y
2. 4 + 2x = y
Hope this helps.
Answer:
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Step-by-step explanation:
I think its the third one
That number is 98. Your Welcome