Answer:
A' = 6(3t +1)
Step-by-step explanation:
The area is the square of the side length, so ...
A = (3t +1)²
The derivative with respect to t is then
A' = 2(3t +1)·(3) = 6(3t +1)
If you like, you can multiply out the area expression first, then differentiate.
A = 9t² +6t +1
A' = 18t +6
This can be factored, if you like, to ...
A' = 6(3t +1)
Answer:
Step-by-step explanation:
The circumference of the outside of a ring is 66 mm and it has an outer diameter of 21 mm. The difference between the outer diameter and the inner diameter of the ring is its thickness. The thickness is constant around the ring. This means that inner outer and circles of the ring are similar. Therefore
Ratio of the outer diameter of the ring to the outer circumference of the ring = ratio of the inner diameter of the ring to the inner circumference of the ring. Therefore
21/66 = inner diameter/50
66× inner diameter = 50 × 21
Inner diameter = 1050/66 = 15.91mm
Answer:
<h2>After two and a half years, there would be 210 volunteers.</h2>
Step-by-step explanation:
Givens
- Each month there are added 5 people.
- The first month there are 125 volunteers.
These problem models a arithmetic sequence, where the difference is 5 and the first term is 125.
Notice that 2 and a half year are equivalent to 18 months. That means we need to find the 18th term,
A arithmetic sequence is defined as
![a_{n}=a_{1}+(n-1)d](https://tex.z-dn.net/?f=a_%7Bn%7D%3Da_%7B1%7D%2B%28n-1%29d)
Where
,
and
.
![a_{18}=125+(18-1)5=125+(17)5=125+85=210](https://tex.z-dn.net/?f=a_%7B18%7D%3D125%2B%2818-1%295%3D125%2B%2817%295%3D125%2B85%3D210)
Therefore, after two and a half years, there would be 210 volunteers.
Answer:
11 pounds
Step-by-step explanation:
88/8=11
Answer:
first one - 30%
second - 15%
third - 40%
fourth - 20%
fifth - 75%
sixth - 70%
seventh - 88%
eighth - 25%
sorry but the last question is too blurry, can you type it and I can help you answer it?
Hope this helps.