All categories

3 years ago

Two numbers, x and y, are randomly chosen from the interval [0,1]. What is the expected value of (x+y)?

2 answers:

7 0

The expression with an interval of [0,1] means all set of numbers including 0 and 1 and numbers within the range. In this case, the minimum sum could be 0 since x and y could be zero. The maximum is 2 since the two variables could be 1. The interval of x+y should be [0 , 2 ].

Igoryamba3 years ago

6 0

It could be 0 and 0 which yeilds a value of 0
it could be 1 and 1 which yields a value of 2

any number from 0 to 2

You might be interested in

How many times does 3 go into 42

trasher [3.6K]

3 goes into 42 14 times

3 0

3 years ago

Given: ABCD is a rhombus, Perimeter = 20, AC:BD = 4:3 Find: Area of ABCD.

REY [17]

4a=20⇒a=5

we know diagonals are perpendicular. if u look at one of the right triangles, you can see that for hypotenuse to be 5, the legs have to be 4 and 3 to satisfy the given ratio 4:3.

so, diagonals are 8 and 6 as we know that diagonals bisect each other.

Area=8*6/2=24

6 0

3 years ago

Given that AC=1 and BC=2 what is AB ?

S_A_V [24]

it would have to be a, because using pythagorean theorem, we can find that a squared + b squared = c squared. substitute that for 1 + b squared = 4; b squared=3 b = square root of 3

3 0

2 years ago

What is the value of x2 + 2y ÷ 2w + 3z for w = 2, x = 5, y = 8, and z = 3?

pav-90 [236]

The answer to this question is 23

5 0

3 years ago

4(a + 2) = 14 – 2(3 – 2a) –2 –1 no solution all real numbers

Ray Of Light [21]

All real numbers.

$\boxed{TRUE}$

Step-by-step explanation:

Distributive property: a(b+c)=ab+ac

Expand: 4(a+2)=4a+8

Expand again: 14-2(3-2a)=4a+8

4a+8=4a+8

You subtract by 8 from both sides of an equation.

4a+8-8=4a+8-8

Simplify.

4a=4a

Then, subtract by 4a from both sides of an equation.

4a-4a=4a-4a

Finally, simplify.

4a-4a=0

0=0

True

All real numbers is the final answer.

Hope this helps you!

Have a nice day! :)

4 0

3 years ago