Answer:
The specific heat of alloy
Explanation:
Mass of the alloy = 30.5 gm = 0.0305 kg
Initial temperature = 93 °c = 366 K
Mass of water = 50 gm = 0.05 kg
Initial temperature = 22 °c = 295 K
Final temperature of the mixture = 31.1 °c = 304.1 K
From the energy conservation principal the heat lost by the alloy is equal to heat gain by the water.
Heat lost by alloy
------- (1)
Heat gain by water
------- (2)
Equation (1) = Equation (2)
This is the specific heat of alloy.