Answer:-
Oxygen gains electrons and is reduced.
Explanation:-
For this reaction the balanced chemical equation is
4Fe + 3O2 --> 2Fe2O3
When Oxygen is present as oxygen gas, the oxidation number of O is Zero since it is the only element present in Oxygen gas.
Similarly Iron is present in Fe with oxidation number Zero.
In the case of Fe2O3, Oxygen has the oxidation number -2 while Iron has +3.
So the oxidation number of Oxygen goes from Zero to -2.
Since the oxidation number decreases Oxygen is reduced.
Since reduction involves gain of electrons, Oxygen gains electrons.
To determine the relative atomic mass of thallium, we multiply the molar mass of the isotopes to their corresponding relative abundance. The molecular percentages should sum up to 1. In this case, we multiply 203 by 0.295 and 205 by 0.705 and add the answers of the two. The final atomic mass is 204.41 g/mol.
Answer: The moles of melatonin are 0.000043
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number
of particles.
To calculate the moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%20%7BMolar%20mass%7D%7D)
Given mass of melatonin = 0.01 g
Molar mass of melatonin
= 232.28 g/mol
![\text{Number of moles of melatonin}=\frac{0.01 g}{232.28g/mol}=0.000043mol](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%20of%20melatonin%7D%3D%5Cfrac%7B0.01%20g%7D%7B232.28g%2Fmol%7D%3D0.000043mol)
Thus the moles of melatonin in 0.01 g are 0.000043
It takes 33.4 s for the concentration of A to fall to one-fourth of its original value.
A <em>half-life</em> is the time it takes for the concentration to fall to half its original value.
Assume the initial concentration is 1.00 mol/L. Then,
![\text{1.00 mol/L }\stackrel{\text{1st half-life }}{\longrightarrow}\text{ 0.50 mol/L } \stackrel{\text{ 2nd half-life }}{\longrightarrow}\text{0.25 mol/L}\\](https://tex.z-dn.net/?f=%5Ctext%7B1.00%20mol%2FL%20%7D%5Cstackrel%7B%5Ctext%7B1st%20half-life%20%7D%7D%7B%5Clongrightarrow%7D%5Ctext%7B%200.50%20mol%2FL%20%7D%20%5Cstackrel%7B%5Ctext%7B%202nd%20half-life%20%7D%7D%7B%5Clongrightarrow%7D%5Ctext%7B0.25%20mol%2FL%7D%5C%5C)
The concentration drops to one-fourth of its initial value in two half-lives.
∴ Time = 2 × 16.7 s = 33.4 s
Answer:
B 1,3
Explanation:
Count the atoms on each side of the arrow, they have to be equal
After arrow
2x C
6x O
4x H
Before the arrow
2x C - correct, as it is the only compound with C then there must only be 1 mole of it.
This is also the correct amount of H
We need 6x O total so 6/2 = 3
So there are 3 moles of O