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Anna11 [10]
3 years ago
15

Which of the following describes a community?

Chemistry
2 answers:
Ostrovityanka [42]3 years ago
7 0
I would say the answer is C
Lapatulllka [165]3 years ago
3 0
Option C most closely describes a community. Ecosystem might be a better word instead of 'community.'
Hope this helps and please give brainliest1
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When forming a chemical bond only the ________ electrons participate in the bonding process.
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The outer shell electrons are only involved in the bonding process since they are the only 'incomplete' shell and it needs to be fulfilled by another element. 
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4 years ago
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dalvyx [7]

it is binary i think

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After scientists use a careful process to gather evidence and establish scientific facts, which step most likely occurs next in
oee [108]

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Conducting Experiments

3 0
2 years ago
The 500kg concrete culvert has a mean radius of 0.5m. part a if the truck has an acceleration of 3m/s2, determine the culvert's
jarptica [38.1K]

<u>Given: </u>

Radius of culvert, r = 0.5 m

Tangential acceleration of the truck, a = 3 m/s2

<u>To determine:</u>

The angular acceleration, α

<u>Explanation:</u>

The tangential acceleration is related to the angular acceleration through the radius as:

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Ans: The angular acceleration is 6 s⁻²


6 0
3 years ago
I need help solving this!
zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol

The given reaction equation is as follows.

C + 2H_{2} \rightarrow CH_{4}

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

5 0
3 years ago
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