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statuscvo [17]
3 years ago
11

15. To draw the Lewis structure of the polyatomic ion, ClO3you would have to _____ those in thestructures of Cl, O, O, and O.a.

add one electron toc. add a proton tob. subtract one electron fromd. subtract a proton from
Chemistry
1 answer:
Contact [7]3 years ago
7 0

To draw the Lewis structure of the polyatomic ion, \mathrm{C} l0_{3} you would have to add one electron to those in the structures of Cl, O, O and O.

Answer: Option A

<u>Explanation:</u>

It is a kind of representation of electrons present in valence shell of each element.  For easy understanding of how the outermost electrons will be arranged for bonding purpose, Lewis structure is used.

As we know that carbon has an outermost electron number of 4. So 4 electrons are required as the electrons in the outermost shell of each carbon. But here only three electrons are there, so one electron need to be added in the Lewis structure of \mathrm{C} l0_{3}.

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3 years ago
How many grams of NaC2H3O2 are needed to prepare 350. mL of a 2.75 M solution? (molar mass of
shepuryov [24]

Answer:

78.96 g of NaC2H3O2

Explanation:

We are given;

  • Volume of the solution as 350 mL
  • Molarity of the solution as 2.75 M
  • Molar mass of the solute NaC2H3O2 as 82.04 g/mol

We are required to determine the mass of the solute;

First we determine the number of moles;

Moles = Molarity × Volume

Therefore;

Moles of the solute = 2.75 M × 0.350 L

                                = 0.9625 moles

Second, we determine the mass

Mass = Moles × Molar mass

        = 0.9625 moles × 82.04 g/mol

        = 78.9635 g

        = 78.96 g

Therefore, the mass of NaC2H3O2 needed is 78.96 g

4 0
3 years ago
Q8. The titration of 15.00 mL of HBr solution of unknown concentration requires 18.44 mL of a 0.100 M KOH solution to reach the
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Answer: 0.123 M

Explanation:

According to the neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HBr solution = ?

V_1 = volume of HBr solution = 15.00 ml

M_2 = molarity of KOH solution = 0.100 M

V_2 = volume of KOH solution = 18.44 ml

n_1 = valency of HBr = 1

n_2 = valency of KOH = 1

1\times M_1\times 15.00=1\times 0.100\times 18.44

M_1=0.123

Therefore, the concentration of the unknown HBr solution is 0.123 M

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Answer:

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