Answer:
+2
Explanation:
Alkaline earth metals are present in group 2 of periodic table. There are six elements in second group. Beryllium, magnesium, calcium, strontium, barium and radium.
All have two valance electrons.
Electronic configuration of Beryllium:
Be = [He] 2s²
Electronic configuration of magnesium.
Mg = [Ne] 3s²
Electronic configuration of calcium.
Ca = [Ar] 4s²
Electronic configuration of strontium.
Sr = [Kr] 5s²
Electronic configuration of barium.
Ba = [Xe] 6s²
Electronic configuration of radium.
Ra = [ Rn] 7s²
They are present in group two and have same number of valance electrons (two valance electrons) and show oxidation state +2 by loosing two valance electrons. They also show similar reactivity.
They react with oxygen and form oxide.
2Ba + O₂ → 2BaO
2Mg + O₂ → 2MgO
2Ca + O₂ → 2CaO
this oxide form hydroxide when react with water,
BaO + H₂O → Ba(OH)₂
MgO + H₂O → Mg(OH)₂
CaO + H₂O → Ca(OH)₂
With sulfur,
Mg + S → MgS
Ca + S → CaS
Ba + S → BaS
Answer:
23.60 mL NaOH
Explanation:
The reaction is CH3COOH + OH- --> CH3COO+ + H2O
Since the reaction is one-to-one, we can use M1V1 = M2V2.
M1 = 0.1894 M CH3COOH
V1 = 25.00 mL CH3COOH
M2 = 0.2006 M NaOH
V2 = ?
Solve for V2 --> V2 = M1V1/M2
V2 = (0.1894 M)(25.00 mL) / (0.2006 M) = 23.60 mL NaOH
Ka x Kb = Kw Kw = 1 x 10⁻¹⁴
(1.3 x 10⁻⁷) x Kb = 1 x 10⁻¹⁴
Kb = ( 1 x 10⁻¹⁴ ) / ( 1.3 x 10⁻⁷)
Kb = 7.7 x 10⁻⁸
Answer D
hope this helps!
Answer:
No
Explanation:
Rust is an iron oxide, a usually reddish-brown oxide formed by the reaction of iron and oxygen in the catalytic presence of water or air moisture.
Explanation:
Carbon dioxide dissolves in water and slowly reacts with water to produce carbonic acid. The cloudy white solution observed when CO2 is bubbled into limewater results from a reaction between Ca(OH)2 and either CO2 or H2CO3 to form an insoluble calcium carbonate precipitate.