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vlabodo [156]
3 years ago
6

The molar mass of lif is 25.94 g/mol. how many moles of lif are present in 10.37 g?

Chemistry
2 answers:
zalisa [80]3 years ago
8 0
Number of moles is (actual mass)/(molar mass)
So there are 10.37/25.94 mols
So there are 0.3998 (or 0.4) moles
Alex_Xolod [135]3 years ago
8 0

Answer : The number of moles of LiF are, 0.399 mole

Explanation : Given,

Mass of LiF = 10.37 g

Molar mass of LiF = 25.94 g/mole

Now we have to calculate the moles of LiF.

\text{Moles of LiF}=\frac{\text{Mass of LiF}}{\text{Molar mass of LiF}}

Now put all the given values in this formula, we get the number of moles of LiF.

\text{Moles of LiF}=\frac{10.37g}{25.94g/mole}=0.399mole

Therefore, the number of moles of LiF are, 0.399 mole

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7 0
2 years ago
At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction:
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<u>Answer:</u> The equilibrium concentration of ICl is 0.27 M

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.45 moles

Initial moles of chlorine gas = 0.45 moles

Volume of the flask = 2.0 L

The molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume}}

Initial concentration of iodine gas = \frac{0.45}{2}=0.225M

Initial concentration of chlorine gas = \frac{0.45}{2}=0.225M

For the given chemical equation:

2ICl(g)\rightarrow I_2(g)+Cl_2(g);K_c=0.11

As, the initial moles of iodine and chlorine are given. So, the reaction will proceed backwards.

The chemical equation becomes:

                      I_2(g)+Cl_2(g)\rightarrow 2ICl(g);K_c=\frac{1}{0.11}=9.091

<u>Initial:</u>         0.225      0.225

<u>At eqllm:</u>   0.225-x    0.225-x     2x

The expression of K_c for above equation follows:

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Putting values in above equation, we get:

9.091=\frac{(2x)^2}{(0.225-x)\times (0.225-x)}\\\\x=0.135,0.668

Neglecting the value of x = 0.668 because equilibrium concentration cannot be greater than the initial concentration

So, equilibrium concentration of ICl = 2x = (2 × 0.135) = 0.27 M

Hence, the equilibrium concentration of ICl is 0.27 M

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