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ICE Princess25 [194]
3 years ago
11

Not only does Snape need to teach his students about hydration states, but also naming hydrates. What is the correct formula for

barium hydroxide octahydrate and magnesium sulfate heptahydrate.
Chemistry
1 answer:
VARVARA [1.3K]3 years ago
5 0

<u>Answer:</u> The chemical formula of barium hydroxide octahydrate is Ba(OH)_2.8H_2O and that of magnesium sulfate heptahydrate is MgSO_4.7H_2O

<u>Explanation:</u>

Ionic compound is defined as the compound which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal (carrying positive charge) and a non-metal (carrying negative charge)

These are usually formed when a metal reacts with a non-metal or a metal reacts with a polyatomic ion or a reaction between two polyatomic ions takes place.

Barium hydroxide octahydrate is formed by the combination of barium ions (Ba^{2+}) and hydroxide ions (OH^{-})

There are 8 water of crystallization around the given compound.

The chemical formula of this compound is Ba(OH)_2.8H_2O

Magnesium sulfate heptahydrate is formed by the combination of magnesium ions (Mg^{2+}) and sulfate ions (SO_4^{2-})

There are 7 water of crystallization around the given compound.

The chemical formula of this compound is MgSO_4.7H_2O

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Explanation:

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3 years ago
What is the mass in grams of 7.5 x 10^15 atoms of nickel, Ni?
statuscvo [17]
<h3>Answer:</h3>

7.3 × 10⁻⁷ g Ni

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.5 × 10¹⁵ atoms Ni

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Ni - 58.69 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 7.5 \cdot 10^{15} \ atoms \ Ni(\frac{1 \ mol \ Ni}{6.022 \cdot 10^{23} \ atoms \ Ni})(\frac{58.69 \ g \ Ni}{1 \ mol \ Ni})
  2. Multiply:                                                                                                           \displaystyle 7.30945 \cdot 10^{-7} \ g \ Ni

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

7.30945 × 10⁻⁷ g Ni ≈ 7.3 × 10⁻⁷ g Ni

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