11/10 MgL work has been done by the tension in the string. If the object has been raised a distance l from rest.
<h3>Define work done?</h3>
The definition of work is expanded so that it encompasses both the forces applied to the body and the overall displacement of the body. A constant force F is present before this block. The objective of this force is to move the body d meters in a straight line in the force's direction.
Given,
Mass of object, M
Acceleration of object, a = g/10
Distance covered vertically, L
Tension of string, T
Work done by tension in string, W
W = T × L
By applying equilibrium force on string,
T - Mg = Ma
g = gravitational acceleration
T - Mg = M (g/10)
T = M(g/10) + Mg
T = 11/10 Mg
By substituting the value in, W = T × L
W = 11/10 Mg × L
W = 11/10 MgL
∴ Work done by tension is 11/10 MgL.
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<span>((P1V1/T1)=(P2V2/T2))</span>
The expected freezing point of the solution is -12.01 °C
<h3>What is the freezing point of a substance?</h3>
The freezing point of a substance is the temperature at which a liquid changes to a solid.
When solutes are dissolved in solvents, they depress the freezing point of the solvent.
The expected freezing point of the solution is calculated using the formula;
where:
- ΔT = freezing point depression
- K = Freezing point constant
- m = molality of the solution
- i = Van't Hoff factor
For water, K = 1.86 ∘c/m
molality of solution = moles of solute/ mass of water in Kg
moles of NaCl = 85/58.5 = 1.453 moles
mass of water in kg = 450/1000 = 0.45
molality of solution = 1.453 / 0.45
molality of solution = 3.23 molal
i = 2
ΔT = 1.86 × 3.23 × 2
ΔT = 12.01
Freezing point of solution = Freezing point of water - ΔT
Freezing point of solution = 0 - 12.01
Freezing point of solution = -12.01 °C
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