It's either B or D because there would be 2 coefficients of hydrogen and one of oxygen
Pb(NO₃)₂ + (NH₄)₂CO₃ → PbCO₃ + 2 NH₄NO₃
Explanation:
Reaction of lead (II) nitrate with ammonium carbonate will produce lead (II) carbonate and ammonium nitrate.
The balanced chemical equation is:
Pb(NO₃)₂ + (NH₄)₂CO₃ → PbCO₃ + 2 NH₄NO₃
To balance the chemical equation the number of atoms of each element
entering the reaction have to be equal to the number of atoms of each
element leaving the reaction, in order to conserve the mass.
Learn more about:
balancing chemical reactions
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Answer: The empirical formula of the compound becomes 
<u>Explanation:</u>
The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.
We are given:
Mass of C = 48.38 g
Mass of H = 6.74 g
Mass of O = 53.5 g
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
......(1)
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Molar mass of C = 12 g/mol
Molar mass of H = 1 g/mol
Molar mass of O = 16 g/mol
Putting values in equation 1, we get:



- <u>Step 2:</u> Calculating the mole ratio of the given elements.
Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 3.023 moles



- <u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of C : H : O = 1 : 2 : 1
Hence, the empirical formula of the compound becomes 
Answer:
These two are equivalent and valid:


Explanation:
The molecular superscripts for each atom in the <em>molecular formula</em> are determined by the number of times that the mass of the<em> empirical formula</em> is contained in the<em> molar mass</em>.
<u />
<u>1. Determine the mass of the empirical formula:</u>
:
Atomic masses:
- O: 15.999g/mol
- C: 12.011g/mol
- N: 14.007g/mol
- Cl: 35.453g/mol
Total mass:
- 15.999g/mol + 12.011g/mol + 14.007g/mol + 35.453g/mol = 77.470g/mol
<u />
<u>2. Divide the molar mass by the mass of the empirical formula:</u>
- 232.41g/mol / 77.470g/mol = 3
<u>3. Multiply each superscript of the empirical formula by the previous quotient: 3</u>

Or:

You might also write CN as a group:
