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4 years ago

How many phosphoester (phosphate ester) and phosphoanhydride bonds are in adenosine and adenosine triphosphate (atp)?

1 answer:

7 0

Phosphate ester bonds exist in adenosine and phosphoanhydride bonds are found in ATP. I think for every two A's, you have 1 phosphate ester bond. Since there are 3 P's in ATP and I think there would only be 2 phosphoanhydride bonds. Hope this answers the question.

You might be interested in

4Na + O2 2Na2O

beks73 [17]

4
N
a
+
O
2
→
2
N
a
2
O
.
By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol
N
a
2
O
should result.
Explanation:
The molecular mass of natrium oxide is
61.98

g
⋅
m
o
l
−
1
. If
5

m
o
l
natrium react, then
5
2

m
o
l
×
61.98

g
⋅
m
o
l
−
1

=

154.95

g
natrium oxide should result.
So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go

5 0

3 years ago

you are running a transformation reaction, and in your microfuge tube currently is your plasmid and your insert fragments (both

ElenaW [278]

A foreign DNA molecule can be incorporated into a bacterial plasmid during a transformation reaction.

<h3>How to explain the reaction?</h3>

With the aid of two enzymes, ligase and restriction enzymes, a foreign DNA molecule can be incorporated into a bacterial plasmid during a transformation reaction. Each enzyme detects a target DNA sequence and cuts it nearby, while ligase aids in connecting the DNA. When two bits of DNA have complimentary bases, it facilitates their joining.

Plasmid and the insert fragment are both present in the microfuge tube, and they both have compatible sticky ends. However, the ligase has been denatured and is no longer active because the prior student left it outside rather than freezing it; despite this, we had already put the ligase into the tube. Ligase aids in binding the plasmid and insert fragments together, but because it is denatured in this instance, it will no longer be able to do so. As a result, no transformation process will take place. And since ligase links DNA fragments together by catalyzing the development of connections between the nearby nucleotides, the two fragments will not be able to unite.

Learn more about reactions on:

brainly.com/question/11231920

#SPJ1

4 0

2 years ago

Describe how experimental evidence led each of the following scientists: Dalton, Rutherford, Thompson, Chadwick and Bohr, to dev

nasty-shy [4]

Dalton Found out there was a small, hard indestructible sphere that is the smalles part of an element.He created his own Atomic Theory:
-All Matter is made up of small particles called atoms.
-Atoms cannot be created, destroyed, or divided into smaller particles.
-All atoms of the same element are identical in mass and size. The atoms of one element are different in mass and size from the atoms of other elements.
-Compounds are created when atoms of different elements link together in definite proportions.
Rutherford had found the positively charged nucleus in the middle of every atom using his Gold Foil Experiment. While doing this experiment, he expected these particles to just pass right through the foil but they bounced right back. He also proposed there were negatively charged electrons revolving around the nucleus.
Thompson found negative electrons and inferred atoms also contain negative particles. He inferred there was a lump of positively charged material, with negative electrons throughout. He used the Raisins Bun Model to explain.
Chadwick proved that it consisted of a neutral particle with about the same mass as a proton "Neutron" is the name given to the particle
Bohr believed Rutherford's prediction was correct, but it wasn't complete. Bohr proposed electrons could only move between energy levels, rather then being able to move everywhere.

6 0

4 years ago

The rate constant for the reaction 3A equals 4b is 6.00×10 how long will it take the concentration of a to drop from 0.75 to 0.2

Lelu [443]

This question is incomplete, the complete question is;

The rate constant for the reaction 3A equals 4B is 6.00 × 10⁻³ L.mol⁻¹min⁻¹.

how long will it take the concentration of A to drop from 0.75 to 0.25M ?

from the unit of the rate constant we know it is a second reaction order

OPTIONS

a) 2.2×10^−3 min

b) 5.5×10^−3 min

c) 180 min

d) 440 min

e) 5.0×10^2 min

Answer:

it will take 440 min for the concentration of A to drop from 0.75 to 0.25M

Option d) 440 min is the correct answer

Explanation:

Given that;

Rate constant K = 6.00 × 10⁻³ L.mol⁻¹min⁻¹

3A → 4B

given that it is a second reaction order;

k = 1/t [ 1/A - 1/A₀]

kt = [ 1/A - 1/A₀]

t = [ 1/A - 1/A₀] / k

K is the rate constant(6.00 × 10⁻³)

A₀ is initial concentration( 0.75 )

A is final concentration(0.25)

t is time required = ?

so we substitute our values into the equation

t = [ (1/0.25) - (1/0.75)] / (6.00 × 10⁻³)

t = 2.6666 / (6.00 × 10⁻³)

t = 444.34 ≈ 440 min {significant figures}

Therefore it will take 440 min for the concentration of A to drop from 0.75 to 0.25M

Option d) 440 min is the correct answer

6 0

3 years ago

A solution is saturated in CO2 gas and KNO3 at room temperature. What happens when the solution is warmed to 75°C?

nignag [31]

Answer:

gaseous CO2 bubbles out of the solution

Explanation:

We already know that the dissolution of a gas in water is exothermic. Hence, when the temperature of a solution containing a gas is increased, the solubility of the gas decreases and the gas bubbles out of the solution.

Similarly, the dissolution of KNO3 in water is endothermic. This implies that the solubility of the solid increases with increasing temperature.

Thus the solid becomes more soluble at 75°.

6 0

3 years ago