Answer:
V₂ = 4.82 L
Explanation:
Given data:
Initial volume of gas = 3.5 L
Initial pressure = 115 Kpa
Final volume = ?
Final Pressure = 625 torr
Solution:
Final Pressure = 625 torr (625/760 =0.82 atm)
Initial pressure = 115 Kpa (115/101 = 1.13 atm)
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
1.13 atm × 3.5 L = 0.82 atm × V₂
V₂ = 3.955 atm. L/0.82 atm
V₂ = 4.82 L
Lattice energy of potassium nitrate (KNO3) = -163.8 kcal/mol
Hydration energy of KNO3 = -155.5 kcal/mole
Heat of solution is the amount of heat absorbed by water when 1 mole of KNO3 is dissolved in it
Heat of solution = Hydration energy - Lattice energy
= -155.5 -(-163.8) = 8.3 kcal/mol
1 kcal/mol = 4.184 kJ/mole
Therefore, 8.3 kcal/mole = 4.184 * 8.3 = 34.73 kJ/mol
Now, 34.73 kJ of heat is absorbed when 1 mole of KNO3 is dissolved
The given 105 kJ of heat would correspond to : 105/34.73 = 3.023 moles of KNO3
Molar mass of KNO3 = 101.1 g/mole
Mass of KNO3 = Molar mass * moles
= 101.1 * 3.023 = 305.63 g = 0.3056 kg
A heterogeneous mixture cannot be considered a single phase
<span>Since Carbon has a chemical name of "C," Hydrogen has "H" and Oxygen has O, we can start with the name "CHO". After this, the next task is to place the proper numbers next to the proper elements. In this case, the representation would be C(6)H(12)O(6), which would be the representation of the simple sugar glucose.</span>
Answer:
The answer is B. Carbonyl
