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valentina_108 [34]
3 years ago
8

Calculate the density of the cube: mass = 150.0 g volume = 16.7 cm3

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
6 0

Answer:

<h3>The answer is 8.98 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass of cube = 150 g

volume = 16.7 cm³

We have

density =  \frac{150}{16.7}  \\  = 8.98203592...

We have the final answer as

<h3>8.98 g/cm³</h3>

Hope this helps you

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3 years ago
The enthalpy change for the explosion of ammonium nitrate with fuel oil is –7198 kJ for every 3 moles of NH4NO3. What is the ent
anastassius [24]

Answer:

−2399.33 kJ

Explanation:

If NH₄NO₃ reacts with fuel oil to give a ΔH of -7198 for every 3 moles of NH₄NO₃

What is the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction

∴ For every 1 mole, we will have \frac{1}{3} of the total enthaply of the 3 moles

so, to determine the 1 mole; we have:

\frac{1}{3}*(-7198kJ)

= −2399.33 kJ

∴ the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction = −2399.33 kJ

7 0
3 years ago
The decomposition of dinitrogen pentaoxide has an activation energy of 102 kJ/mol and ΔH°rxn = + 55 kJ/mol. What is the activati
ahrayia [7]

<u>Answer:</u> The activation energy of the reverse reaction is 47 kJ/mol

<u>Explanation:</u>

The chemical equation for the decomposition of dinitrogen pentaoxide follows:

N_2O_5\rightleftharpoons 2NO_2+\frac{1}{2}O_2

We are given:

Activation energy of the above reaction (forward reaction) = 102 kJ/mol

Enthalpy of the reaction = +55 kJ/mol

As, the enthalpy of the reaction is positive, the reaction is said to be endothermic in nature.

To calculate the activation energy for the reverse reaction, we use the equation:

E_a_{\text{(forward)}}=E_a_{\text{(backward)}}+|\Delta H|

where,

E_a_{\text{(forward)}} = Activation energy of the forward reaction = 102 kJ/mol

E_a_{\text{(backward)}} = Activation energy of the backward reaction = ?

\Delta H = Enthalpy of the reaction = +55 kJ/mol

Putting values in above equation, we get:

102=E_a_{\text{(backward)}}+55\\\\E_a_{\text{(backward)}}=(102-55)=+47kJ/mol

Hence, the activation energy of the reverse reaction is 47 kJ/mol

3 0
3 years ago
How many atoms are in 1.14 mol of sulfur trioxide
yawa3891 [41]
2.75 x 10^24

Hope this helped :)
8 0
3 years ago
A 3.0 g sample of a gas occupies a volume of 1.00L at 100C and 740 torr pressure. The molecular weight of the
SOVA2 [1]

Answer:

94.2 g/mol

Explanation:

Ideal Gases Law can useful to solve this

P . V = n . R . T

We need to make some conversions

740 Torr . 1 atm/ 760 Torr = 0.974 atm

100°C + 273 = 373K

Let's replace the values

0.974 atm . 1 L = n . 0.082 L.atm/ mol.K . 373K

n will determine the number of moles

(0.974 atm . 1 L) / (0.082 L.atm/ mol.K . 373K)

n = 0.032 moles

This amount is the weigh for 3 g of gas. How many grams does 1 mol weighs?

Molecular weight → g/mol → 3 g/0.032 moles = 94.2 g/mol

3 0
3 years ago
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