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Ira Lisetskai [31]
3 years ago
11

A(n) _______________ is a negatively charged ion

Chemistry
2 answers:
siniylev [52]3 years ago
3 0
An anion is a negatively charged ion. 

Hope this helps xox :)
kolezko [41]3 years ago
3 0
Im sure a negatively ion is a negatively charge ion
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Pls someone help me with this question pls
astra-53 [7]
The answer should be c because of the answer
3 0
3 years ago
What substance can be split into simpler substances by similar means?
Cerrena [4.2K]

Answer:

c

Explanation:mark me brainliest plz thanks

6 0
3 years ago
Read 2 more answers
The Cr 3+ ion forms octahedral complexes with three neutral ligands X, Y, and Z. The color of CrX 6 3+ is blue; the color of CrY
sergeinik [125]

Answer:The statement which is false is d

Explanation:

The color which we  see from our eyes is basically the complementary color of wavelength of light which is absorbed.

The wavelegth of light follows the following sequence:

Violet<Indigo<Blue<Green<Yellow<Orange<Red.

So the shortest wavelegth is of violet light and longest wavelength of light is Red.

Since energy is E=hv=hc/λ ;So energy is inversely related with wavelegth and hence

For ligand X the complex has blue color and so we can ascertain that ligand X would have absorbed the Red light as the complementary color of blue light is Red.So the complex of ligand X absorbs the longest wavelegth and hence  the energy gap between the two split d-orbitals t2g and eg  would be very less. Larger the energy gap between t2g and eg orbitals more stronger is the ligand .

So X would be a weak field ligand.

For ligand Y the complex has yellow color and so we can ascertain that ligand Y would have absorbed the Violet  light as the complementary color of yellow light is  violet. Violet has the lowest wavelegth and hence  the energy gap between the two split d-orbitals t2g and eg  would be very large. Larger the energy gap between t2g and eg orbitals more stronger is the ligand .

So Y is a strong field ligand.

For ligand Z the complex has red color and so we can ascertain that ligand Z would have absorbed the blue  light as the complementary color of red light is  blue.The wavelegth of  blue light lies between  violet and red hence  the energy gap between the two split d-orbitals t2g and eg  would be  in between than the other two liagnds.

So Z would be moderate field ligand.

options A , B and C are correct statements.

option D is incorrect because Z absorbs the moderate wavelegth.

The answer is d as it is only statement which is incorrect.

6 0
3 years ago
The rate of formation of C in the reaction 2 A + B →2 C + 3 D is 2.7 mol dm−3 s −1 . State the reaction rate, and the rates of f
Zielflug [23.3K]

Answer:

Rate of reaction =1.35mol.dm^{-3}.s^{-1}

Rate of consumption of A = 2.7mol.dm^{-3}.s^{-1}

Rate of consumption of B = 1.35mol.dm^{-3}.s^{-1}

Rate of formation of D = 4.15mol.dm^{-3}.s^{-1}

Explanation:

According to laws of mass action for the given reaction,

Rate= -\frac{1}{2}\frac{\Delta [A]}{\Delta t}=-\frac{\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}=\frac{1}{3}\frac{\Delta [D]}{\Delta t}

where, -\frac{\Delta [A]}{\Delta t} is rate of consumption of A, -\frac{\Delta [B]}{\Delta t} is rate of consumption of B, \frac{\Delta [C]}{\Delta t} is rate of formation of C and \frac{\Delta [D]}{\Delta t} is rate of formation of D

Here \frac{\Delta [C]}{\Delta t}=2.7mol.dm^{-3}.s^{-1}

So, Rate of reaction = (\frac{1}{2}\times 2.7mol.dm^{-3}.s^{-1})=1.35mol.dm^{-3}.s^{-1}

Rate of formation of D = (\frac{3}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{3}{2}\times 2.7mol.dm^{-3}.s^{-1})=4.15mol.dm^{-3}.s^{-1}

Rate of consumption of A = (\frac{2}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{2}{2}\times 2.7mol.dm^{-3}.s^{-1})=2.7mol.dm^{-3}.s^{-1}

Rate of consumption of B = (\frac{1}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{1}{2}\times 2.7mol.dm^{-3}.s^{-1})=1.35mol.dm^{-3}.s^{-1}

3 0
3 years ago
Quinine (C20H24N2O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine
dolphi86 [110]

Answer:

The pH of saturated solution of the quinine is 10.05

Explanation:

Quinine (Q) is C20H24N2O2 has a molar mass of 324.4 g/mol

Q can behave as a weak base. Kb and pKb can be calculated for weak bases

pKb1 is to be considered when solving the question.

pKb1 = 5.1

Step 1 : Calculate the Kb of Quinine

            pKb1 = - log [kb]

                5.1  = - log [kb]

                take Antilog of both side

             [kb] = 7.94 x 10∧-6

Step 2: Calculate the concentration of saturated solution of Q in mol/dm3

           From the question, 1900 ml of solution contains 1 g of Q

           Therefore,  1000 ml of solution will contain........... x g of Q

           x = 1000 /1900

           x = 0.526 g in 1 dm3

In calculating concentration in mol/dm3,

Concentration in mol/dm3 = concentration in g /dm3 divided by molar mass

Molar mass of Q = 324.4

Concentration in mol/dm = 0.526 /324.4

                                         = 0.0016 mol/dm3

Step 3: Calculating the Concentration of OH-

            At Equilibrium, Kb = x² / 0.0016

            7.94 x 10∧-6 = x² / 0.0016

            x = √ 0.0016 × 7.94 x 10∧-6

            x = 1. 127 × 10∧-4 mol/dm3

The concentration of OH- = 1. 127 × 10∧-4 mol/dm

Step 4:  Calculating the pH of Quinine

           Recall, pOH = - log [OH-]

           pOH = - log [1. 127 × 10∧-4]

           pOH = 3.948

           Also recall that pH + pOH = 14

           pH = 14 - 3.948

           pH = 10.05

           

8 0
4 years ago
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