Answer:
Rubidium
Explanation:
Rubidium has atomic number 37 and belong to group one alkali metals and has one valence electron at the outermost shell whiz is 5s1
Answer:
About 16.1 grams of oxygen gas.
Explanation:
The reaction between magnesium and oxygen can be described by the equation:

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.
Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:
- Convert grams of MgO to moles of MgO.
- Moles of MgO to moles of O₂
- And moles of O₂ to grams of O₂.
The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.
Dimensional analysis:

In conclusion, about 16.1 grams of oxygen gas was reacted.
You will obtain the same result if you compute with the 24.4 grams of Mg instead:

No, xenon will not react on Nitrogen because xenon only reacts with oxygen and fluorine. Xenon only reacts with the 2 elements because these 2 elements contain a strong electronegative element which is high in energy barrier that can move the electrons inside xenon elements. Xenon is an element with a symbol of Xe, it is odorless and colorless gas. Common uses of xenon are flash lamps and arc lamps. Xenon is a luminous element, it glows when placed near to high voltage electric field.
Answer:
18.095 %.
Explanation:Theoretical yield is the yield calculated from the balanced chemical equation. In this reaction theoretical yield is 21g. Actual yield = 3.8g. Hence, the percent yield for this reaction is 18.095 %.
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